Question

Choose the correct simplification of the expression (3x)4.
Need help understanding this.

Answer 1

Is this multiple choice? What course/grade level is this?

Answer 2

9th algebra 2

Answer 3

and yes it is

Answer 4

Ok, so what does numbers besides brackets usually represent
(HINT- BEDMAS or PEDMAS)

Answer 5

81x4

12x5

81x5

12x4

Answer 6

is x a variable here? OR is that a multiplication sign?

Answer 7

x variable

Answer 8

Should we assume this is

\[(3x)^4\]

?

Answer 9

yes

Answer 10

Oh. That makes it so much more understandable.

Answer 11

Sorry I'm just really tired and my mother not letting me get off the laptop till I finsh 12 assignments..

Answer 12

Understandable. I think John has some help for you.

Answer 13

\[(3x)^4 = 3^4 \times x^4\]

Since this exponent is separated from the number and variable via the parenthesis...you apply it to each one inside the parenthesis...

So what is 3^4?

Answer 14

81?

Answer 15

Correct....and what is 81 times x^4?

Answer 16

81x^4?

Answer 17

Right...which looks a lot like answer choice...?

Answer 18

Oh that make sense. Thank you

Answer 19

Do you think you can help me with another one?

Answer 20

Right...

And remember this can also have been written as

\[(3x)^4 = (3x)(3x)(3x)(3x)\]

3x times 3x = 9x^2 so...

\[(9x^2)(3x)(3x)\]

9x^2 times 3x = 27x^3 so...

\[(27x^3)(3x)\]

And finally 27x^3 times 3x = 81x^4

\[(81x^4)\]

Answer 21

Thanks for the medal by the way @IsTim

and sure @BlackLai if I can't then someone else I'm sure will!

Answer 22

Alright

Answer 23

Choose the correct simplification of the expression b5 • b4.

b

b^9

b^20

b^−1

Answer 24

Its important to know...that when you are multiplying exponents with the same base...you add the exponents and leave the base alone

\[b^5 \cdot b^4 = b^{5 + 4}\]

Answer 25

Oh.

Answer 26

I think I understand abit.

Answer 27

Yeah just remember some rules

\[\large{x^a} \cdot {x ^b} = x^{a + b}\]
\[\large \frac{ x^a }{ x^b } = x^{a - b}\]
\[\large (x^a)^b = x^{a \times b}\]

Answer 28

Oh okay.

Answer 29

So for b^5+^4 Do i add add 5+4 then use the exponents to m?ultiply

Answer 30

multiply*

Answer 31

wait...what? The question from before?

\[b^5 \times b^4\]
?

Answer 32

mhm

Answer 33

b^5+^4 <----- this what would i have to do get the answer that I need?

Answer 34

?

Answer 35

sorry about that...there a mass tagger that keeps calling people to questions lol...

you would do

b^(5 + 4) and b^9 would be your final answer...just add the exponents...no multiplication here

Answer 36

Oh okay, you have been really helpful I appericate it.

Answer 37

So for multiple dat uses the same variable ex: d^3 x d^5

Answer 38

I would use the same method that you did for my previous question?

Answer 39

Yes. but I'm only inferring this from the last few comments.

Answer 40

Right same method....when the exponents have the same base *as these do..the base is 'd'...you ignore the base...and you add the exponents

Answer 41

Okay, I believe I understand it now.

Answer 42

You made it much more clearer for me thank you.

Answer 43

No problem!

Answer 44

There's two more i need assist with are you still free to help?

Answer 45

Yeah sure

Answer 46

Choose the correct simplification of the expression (a2)3.

a5

a8

a

a6

Answer 47

(a^2)^3*

Answer 48

So remember what I said with these ones

\[\large (x^a)^b = x^{a \times b}\]

Answer 49

Yeah

Answer 50

So you would use that rule

\[\huge(a^2)^3 = a^{2 \times 3} = a^{?}\]

Answer 51

a^6?

Answer 52

That is correct!

Answer 53

Thank you.

Answer 54

Choose the correct simplification of the expression (xyz^2)^4.

x^5y^5z^6

x^5y^5z^8

xyz^16

x^4y^4z^8

Answer 55

Okay now this is just a spin off of the last rule

\[\large(xyz^2)^4 = x^4 \times y^4 \times z^{2 \times 4}\]

Just remember you apply it to every variable in the equation

Answer 56

Oh okay.

Answer 57

So how would i get my answer off this one owo

Answer 58

Well like I showed above...you have x^4 and y^4 and z^(2 times 4) so z^8

Which choice is that?

Answer 59

Oh I got it now

Answer 60

Theres this last one if u wish to help me. .?

Answer 61

Sure why not lol

Answer 62

Part 1: Explain, using complete sentences, how to simplify the expression below.
Part 2: What is the simplified expression?

(3x3y4)(2x2y6)

Answer 63

\[\large(3x^3y^4)(2x^2y^6)\]

like that?

Answer 64

(3x^3y^4)(2x^2y^6)*

Answer 65

ye

Answer 66

So we can break this up a bit

The numbers first...
what is 3 times 2?

Answer 67

6

Answer 68

Right...

what is x^3 times x^2?
*hint*
\[\huge x^3 \times x^2 = x^{3 + 2}\]

Answer 69

X^3+2 = X^5

Answer 70

Right....and finally what is

y^4 times y^6?
*hint*

\[\huge y^4 \times y^6 = y^{4 + 6}\]

Answer 71

Y^4+6= Y^10

Answer 72

Great...so altogether we have

\[\large 6x^5y^{10}\]

Answer 73

So no signs in the middle of those equations?

Answer 74

None at all...there were none to begin with so there are none to end with

Answer 75

ah

Answer 76

In a way how would I explain it in complete sentence?

Answer 77

Hmm...when you multiply these 2 together....you multiply the coefficients.....add the exponents of the base 'x' and add the exponents of the base 'y' to get 6x^5y^10

Idk something like that I guess lol

Answer 78

lol That understandable

Answer 79

Well that all for now thank you again for all your help.

Answer 80

lol no problem man!