Question

Which system of equations matches the graph below?

graph of a line starting at a closed circle at (1, negative 2) and passing through (2, 0). The second graph is a partial parabola starting at an open circle at (1, 0) and continuing through point (negative 1, 0)

y = x2 – 1 if x < 1
y = 2x – 4 if x greater than or equal to –2

y = x2 – 1 if x > –1
y = 2x – 4 if x greater than or equal to –2

y = x2 – 1 if x < 1
y = 2x – 4 if x greater than or equal to 1

y = x2 – 1 if x < 0
y = 2x – 4 if x greater than or equal to –2

Answer 1

@ivettef365

Answer 2

@Jonask

Answer 3

There is an easy way to solve this by looking only at the line. You don't even have to get the slope and do the point-slope equation and go to the slope-intercept, because all equations for the line are the same. All you have to do for this problem is look at the domain for "x". Choice #3 is the only one that recognizes all points.

Answer 4

oh ok

Answer 5

By looking at the graph of the line, we see that we need points for x = 1 and all x greater than 1, so it has to be choice #3 without even looking at the parabola.

Answer 6

All good now, @topstryker ?

Answer 7

umm How many times will the graph of y = x2 intersect the graph of y = –x2?

Answer 8

2?

Answer 9

New questions should be in new posts. Intersection only at the origin.