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HELP!!! Using the formula for continuous compounding of interest: A = Pe^rt, find the time necessary for $1000 to double at 6 1/2% interest.
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Plugging in our variables, we get: \[2P=Pe^{.065t}\]where P is the initial amount. Divide both sides by P: \[2=e^{.065t}\]Next you'll want to take the natural log of both sides to eliminate the e: \[\ln2=.065t\]Can you solve for t from here?
Yes! So t = 10.6638. Therefore, 10 years, right?
Right, it would be about 10.66 years.
Okay, thank you so much!
You're welcome, glad I could help
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