Question

Can someone show me how to do this please?

Answer 1

@amistre64 @agent0smith @Blaze @brianjr227 @countonme123 @Claflamme3 @DLS @divagirl421 @ehmuleeee @espresso @foreverandalways13 @goformit100 @ganeshie8 @Hero @helpme1112 @ivettef365 @IsTim @johnweldon1993 @Jonask @khurramshahzad @kayboo2013 @LazyBoy @leahhbe @mathstudent55 @mathslover @Mashy @NaCl @nocontact115 @Preetha @physicsboffin

Answer 2

I call these the AP people..

Answer 3

You use the distance formula... do you know what that is?

Answer 4

LMAO why thank you :)

Answer 5

@Claflamme3 no I don't know that formula

Answer 6

((0-1)^2+(0-3)^2)^(1/2)

Answer 7

\[d = \sqrt{x_2 - x_1)^2 + (y_2 - y_1)^2}\]

So what are your coordinates of your new A and B?

Answer 8

yup ryt mr @johnweldon1993

Answer 9

So the coordinate of your new A point....looks to be (2,1) and the coordinate of your new B point...looks to be (3,4)

(2,1) (3,4)
(x1,y1)(x2,y2)
So you would plug in these number as so

\[d = \sqrt{(3 - 2)^2 + (4 - 1)^2}\]

And simplify

Answer 10

u can take AB or A`B` both are equal actually

Answer 11

Yeah I know....just figured that since it has the A' and B' notation *after transformation...might as well use it lol

But yes both are equal

Answer 12

My answers for my first x and y are messed up for some reason. Other than that I got the formula process right I guess.

Answer 13

\[\sqrt{(3-2)^{2}+(4-1)^{2}}\]
\[\sqrt{1+9}\]
\[\sqrt{10} =Answer \]
* Answer teacher approved

Answer 14

lol That is correct :) Good work!