Question

Divide the following polynomial (27x^2-9a)/(3)

Answer 1

Ok so we don't have to do anything fancy like long division for this one.
We just need to remember how fractions work.

\[\large \frac{a+b}{c} \qquad=\qquad \frac{a}{c}+\frac{b}{c}\]

Answer 2

So for our problem, we have,\[\large \frac{27x^2-9a}{3} \qquad=\qquad \frac{27x^2}{3}+\frac{-9a}{3}\]

Answer 3

From there, just divide each coefficient by 3.

27/3 = ?

Answer 4

9

Answer 5

take look on screen the answer should fit on grid so they give 9 to start

Answer 6

you got 9 for the first coefficient? Ok good.
The x^2 won't change, only the coefficient.\[\large 9x^2+\frac{-9a}{3}\]

How bout the other one? -9/3=?

Answer 7

thats -3

Answer 8

Ok good.
\[\large 9x^2-3a\]

Having any trouble putting the symbols in correctly?

Answer 9

no

Answer 10

k cool

Answer 11

(6x^3+11x^2-4x-4)/(3x-2) im stuck on this one too same thing

Answer 12

2x+7 is the answer to (6x^3+11x^2-4x-4)/(3x-2)