Question

Divide the following polynomial (6x^3+11x^2-4x-4)/(3x-2)

Answer 1

well first simplify
(6x^3 + 11x^2 - 4x - 4) / (3x - 2)
(6x^3 + 11x^2) - (4x - 4) / (3x - 2)
x^2(6x + 11) - 4 (x - 1) / (3x - 2)
I don't think you can divide the polynomial it does not work out.

Answer 2

@friedRice but its long division

Answer 3

yeah I changed it into long division and it did not work

Answer 4

(here is what they say)
You have to use a method called polynomial long division.
I found this question divides with no remainder, My answer was 2x^2+5x+2.

Answer 5

(6x + 11)(x + 1)(x^2 - 4) / (3x -2)

Answer 6

that's long division

Answer 7

http://answers.yahoo.com/question/index?qid=20091130113724AALK51f

Answer 8

check

Answer 9

(x 2 - 4)/ (x - 1) that's not long division but my answer doesn't match to put on grid

Answer 10

different problem

Answer 11

take look that's how it should looks like

Answer 12

(x^2 -4) / (x - 1)
(x + 2)(x - 2) / (x - 1)

well I don't know but if yahoo does it like that you will get something

Answer 13

and the other people did not divide right

Answer 14

look
3x - 2 | 6x^3+11x^2-4x-4 |
2x^2 + 5x +2 6x^3 - 4x^2 (-)

Answer 15

carefully

Answer 16

did you found the answer?

Answer 17

from dividing 3x - 2

Answer 18

@FriedRice yeah so what you think witch answer?

Answer 19

@FriedRice well 11/5 = 5.5 they just removed point i think

Answer 20

lets ask a mentor

Answer 21

who is mentor?

Answer 22

lets check

Answer 23

be right back

Answer 24

ok

Answer 25

@amistre64 @Hero @ash2326

Answer 26

well, long division is soo passe; synthetic division is a much better process

Answer 27

Divide the following polynomial (6x^3+11x^2-4x-4)/(3x-2)

Answer 28

6x^3 + 11x^2 - 4x - 4
0 4 10 4
2/3 6 15 6 0

Answer 29

\[\frac{6x^3+11x^2-4x-4}{3x-2}\]
\[\frac13\frac{6x^3+11x^2-4x-4}{x-\cfrac23}\]

Answer 30

2x^2 + 5x + 2

Answer 31

im confused how you got 5

Answer 32

15/3 = 5

Answer 33

where you got 15?

Answer 34

nvmyou added 4

Answer 35

i used sythetic division to make the process simpler

Answer 36

amister64 do you know any online calculator that solves those kind problems?

Answer 37

i just use wolfram if i need to dbl chk stuff

Answer 38

i did it to but it seems showing me diffrent answers

Answer 39

(x^2 - 4)/(x - 1) i tryed put this on wolfram and can't find the answer

Answer 40

didn't find the answer to match this look on screen

Answer 41

if we do long hand


(6x^2 + 15x + 6 ) /3
-----------------------
x-2/3 | 6x^3 + 11x^2 - 4x - 4
-(6x^3 -4x^2)
--------------
15x^2 - 4x
-(15x^2-10x)
-------------
6x - 4
-(6x - 4)
---------
0


(6x^2 + 15x + 6 ) /3 = 2x^2 +5x + 2

Answer 42

(x^2 - 4)/(x - 1) i tryed put this on wolfram and can't find the answer

Answer 43

help me with this one

Answer 44

x^2 + 0x - 4
0 1 1
1 1 1 -3

\[{x+1-\frac{3}{x-1}}{}\]

Answer 45

can you show how did you put on wolfram

Answer 46

http://www.wolframalpha.com/input/?i=%28x%5E2+-+4%29%2F%28x+-+1%29

Answer 47

i had same thing but where you see the answer?

Answer 48

if you type simplify in front of it you get alternate forms

Answer 49

http://www.wolframalpha.com/input/?i=simplify+%28x%5E2+-+4%29%2F%28x+-+1%29

Answer 50

there is no "one" alternative

Answer 51

the answer you gave me i can't find on wolfram umm can you screen and circle with red the answer

Answer 52

its the first one ... remember that addition of terms is not specific to position

1 + 2 + 3 is equal to the same setup as: 3 + 1 + 2

Answer 53

look

Answer 54

so you moved 1 from the end?

Answer 55

i tend to put the remainder at the end of a quotient string ... the wolf seems to feel it more appropriate to place a constant at the end

Answer 56

http://www.wolframalpha.com/input/?i=simplify+%28a^+%282n%29+-+a^n+-+6%29%2F%28a^n+%2B+8%29 check this out

Answer 57

where is the answer for this one

Answer 58

all three results that they show are equally valid. You are pretty much asking if:

\(1.75\), or \(1\cfrac34\), or \(\left(1+\cfrac34\right)\), or \(\left(\cfrac34+1\right)\), or \(\cfrac{7}{4}\) ... is more correct

Answer 59

(a^ (2n) - a^n - 6)/(a^n + 8) <---- for this problem?

Answer 60

yes, and for the rest of your problems as well

Answer 61

is can be written in several different ways .... which way is the "correct" way? that depends on whoever wants to grade the work

Answer 62

it gives you 4 different ways to write it out ... they are all equal to each other

Answer 63

here how it should look in my problem i don't know witch one to choice

Answer 64

the first one then

Answer 65

when i start putting symbols in a^2+[ ] [ ] their is 2 spaces before other parts begin

Answer 66

then since you cant possible fit -9 at the end of it ... plug it in the middle of it

Answer 67

but a^2+-9 you think that will work?

Answer 68

of course not .... a^2 - 9 + ________

Answer 69

oh ok got it:)so confusing hate polynomials now

Answer 70

its not really the polys fault, its that rediculous program you have to fight with ....

Answer 71

wolf?

Answer 72

yeah, the wolf is making you fill in boxes in a specific manner ....

Answer 73

now all fits :) so i need to rember if at the end has numbers such as -9 i put in middle right?

Answer 74

i would, it looks like your program there does what i do, tag the remainder on the end.

Answer 75

alright thank you for helping me out gave you medal :)

Answer 76

youre welcome

Answer 77

have nice day