Question

what is the simplified form of x/3-y/4/x/4+y/3

Answer 1

Is this what the problem looks like?\[\large \frac{x}{3}-\frac{\left(\dfrac{y}{4}\right)}{\left(\dfrac{x}{4}\right)}+\frac{y}{3}\]

The brackets are to show which fraction belongs where, otherwise the problem doesn't make sense D:

Answer 2

yessir @zepdrix

Answer 3

When dividing fractions, we can rewrite it as multiplication by flipping the bottom fraction.\[\large \frac{\left(\dfrac{y}{4}\right)}{\left(\dfrac{x}{4}\right)} \qquad=\qquad \frac{y}{4}\cdot \frac{4}{x}\]

Answer 4

The 4's will divide out giving us,\[\large \frac{4y}{4x}=\frac{y}{x}\]


Simplifying the middle term leaves us with,\[\large \frac x3-\frac yx+\frac y3\]

Answer 5

From here, you need to get a common denominator.
In this case it will be 3 times x.

\[\large \left(\frac{x}{x}\right)\frac x3-\left(\frac{3}{3}\right)\frac yx+\left(\frac{x}{x}\right)\frac y3\]
\[\large \frac{x^2}{3x}-\frac{3y}{3x}+\frac{xy}{3x} \qquad=\qquad \frac{x^2+xy-3y}{3x}\]

Hmm this is a weird problem :O you sure we had the fractions correct at the start?

Answer 6

yeaaaap lol