Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

how do I simpifly this, please show steps!(see pic below)

OpenStudy (anonymous):

\[6\sqrt{2}-3\sqrt{2}\]

OpenStudy (phi):

if it were 6 x - 3 x what would the answer be ?

OpenStudy (phi):

you have 6 of something and take away 3 of the same thing. what do you have left ?

OpenStudy (anonymous):

3 if you take 3 from each side? @phi

OpenStudy (phi):

there is only 1 "side" (you only have sides if you have an equation) this is just 6 of something , take away 3 of that something

OpenStudy (phi):

if it were 6 cows, take away 3 cows, how many cows ? this is almost the same thing, except instead of cows you have square roots of 2

OpenStudy (radar):

Let's do this the hard way, First factor the expression:\[3\sqrt{2}(2-1) = 3\sqrt{2}(1)= 3\sqrt{2}\]

OpenStudy (radar):

I'm sure that cleared that up even to the most casual observer, ........lol

OpenStudy (anonymous):

if you take away 3 from six you got three, will you please do it step by step on the equation drawing thing

OpenStudy (phi):

yes, you have \[ 6 \sqrt{2} - 3 \sqrt{2} = 3 \sqrt{2} \] that says you have 6 sqrt(2) and take away 3 sqrt(2), leaving 3 sqrt(2)

OpenStudy (phi):

the main idea is sqrt(2) is a number. Treat it like any other number. For example, if the problem was six 2's take away three 2's you are left with three 2's it is the same for sqrt(2)

OpenStudy (anonymous):

okay, I think I got that last part?

OpenStudy (phi):

another way to think of the problem is \[ 6 \sqrt{2} = \sqrt{2} +\sqrt{2} +\sqrt{2} +\sqrt{2} +\sqrt{2} +\sqrt{2} \] and \[ 3 \sqrt{2} = \sqrt{2} +\sqrt{2} +\sqrt{2} \] and \\[ 6 \sqrt{2} - 3 \sqrt{2} = \sqrt{2} +\sqrt{2} +\sqrt{2} +\sqrt{2} +\sqrt{2} +\sqrt{2} - \sqrt{2} - \sqrt{2} - \sqrt{2} \]

OpenStudy (phi):

another way to think of it is use factoring like radar: \[ 6 \sqrt{2} - 3\sqrt{2}= \sqrt{2}(6-3) \] by "factoring out sqrt(2)" simplify 6-3 to get 3 and the answer \[ \sqrt{2} \cdot 3 \] which is normally written with the 3 in front (but order does not matter when multiplying... it just looks nicer with the 3 in front) \[ 3 \sqrt{2} \]

OpenStudy (phi):

do any of those make sense ?

OpenStudy (phi):

personally, I like to think it is the same as thinking of sqrt(2) as a cow, and we subtract cows.

OpenStudy (anonymous):

thank you these last ones helped me a lot!

OpenStudy (anonymous):

\[3\sqrt{2}\] @phi would this be the answer?

OpenStudy (radar):

That does agree with my first post.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!