Can someone walk me through the steps to make sure that I am doing the right thing? Eliminate the parameter in the parametric equations x = (1/4)t and y = t2 and write the rectangular equation whose graph represents the curve.
I think it is y=16x^2
yes
So that is the right answer?
yes. x = (1/4) t so t = 4x (multiply both sides by 4) and t^2 = 16x^2 (square both sides) they say y = t^2 to y = 16 x^2
Now the plus or minus from the square root goes away at the end, right?
I doesn't matter, correct?
what square root ? you start with x = (1/4)t and y = t^2 if you do as posted above, you never take the square root.
Oh. Nevermind... Lol.
Thanks. I looked at the wrong problem.
you could do y = t^2 sqrt(y)= t x= (1/4)*sqrt(y) and you probably should take just the positive root
Yeah, that's what I did... Ah! It's been a long week..., but thanks.
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