Use basic identities to simplify the expression [csc(θ) x cot(θ)]/sec(θ)
What's the question?
what do you want????
Use basic identities to simplify the expression
ok, What are the definition of the following: csc(x) = ? cot(x) = ? sec(x) = ?
csc = 1/sin cot = 1/tan sec = 1/cos
substitute those^^ in the problem
put all in terms of sin and cos and then simplify
but only work with one side
here there is only one side......it just has to be simplified
Your original express now becomes \[\frac{ \frac{ 1 }{ \sin(x) }\frac{ 1 }{ \tan(x) } }{ \frac{ 1 }{ \cos(x) } }\] can you simplify it any further? What is the definition of tan(x)?
so (1/sin) x (cos/1)=cos/sin (1/tan) x (cos/1)=cos/tan tan = sin/cos
[csc(θ) x cot(θ)]/sec(θ) \[\frac{ \frac{ 1 }{ \sin \theta }*\frac{ \cos \theta }{ \sin \theta } }{ \frac{ 1 }{ \cos } }\]
then this gives\[\frac{ \frac{ \cos \theta }{ \sin ^{2}\theta } }{ \frac{ 1 }{ \cos \theta }}\] further \[\frac{ \cos \theta }{ \sin ^{2}\theta }*\frac{ \cos \theta }{ 1 }
Excuse me Harkirat, but I don't understand what you are saying with the whole \[\frac{ \frac{ 1 }{ . How do I interpret that?
sorry, it did not come out right....\[\frac{ \cos \theta }{ \sin ^{2}\theta }*\frac{ \cos \theta }{ 1 }\] now resolve this to get your answer
Going off of what @Harkirat said, we just need to calculate \[\frac{ \frac{ \cos(\theta) }{\sin ^{2}(\theta) }} { \frac{ 1 }{ \cos(\theta) } } = \frac{ \cos(\theta) }{\sin ^{2}(\theta) } \frac{ \cos(\theta) }{ 1 } = \frac{ \cos ^{2}(\theta) }{ \sin ^{2}(\theta) }\]
Finally \[\frac{ \cos ^{2}\theta }{ \sin ^{2}\theta }=\left( \frac{ \cos \theta }{ \sin \theta } \right)^{2}=\cot ^{2}\]
I'm confused
what part confuses you???
Do I have this right? |dw:1374179350798:dw|
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