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Mathematics 17 Online
OpenStudy (anonymous):

Use basic identities to simplify the expression [csc(θ) x cot(θ)]/sec(θ)

OpenStudy (anonymous):

What's the question?

OpenStudy (anonymous):

what do you want????

OpenStudy (anonymous):

Use basic identities to simplify the expression

OpenStudy (anonymous):

ok, What are the definition of the following: csc(x) = ? cot(x) = ? sec(x) = ?

OpenStudy (anonymous):

csc = 1/sin cot = 1/tan sec = 1/cos

OpenStudy (anonymous):

substitute those^^ in the problem

OpenStudy (anonymous):

put all in terms of sin and cos and then simplify

OpenStudy (anonymous):

but only work with one side

OpenStudy (anonymous):

here there is only one side......it just has to be simplified

OpenStudy (anonymous):

Your original express now becomes \[\frac{ \frac{ 1 }{ \sin(x) }\frac{ 1 }{ \tan(x) } }{ \frac{ 1 }{ \cos(x) } }\] can you simplify it any further? What is the definition of tan(x)?

OpenStudy (anonymous):

so (1/sin) x (cos/1)=cos/sin (1/tan) x (cos/1)=cos/tan tan = sin/cos

OpenStudy (anonymous):

[csc(θ) x cot(θ)]/sec(θ) \[\frac{ \frac{ 1 }{ \sin \theta }*\frac{ \cos \theta }{ \sin \theta } }{ \frac{ 1 }{ \cos } }\]

OpenStudy (anonymous):

then this gives\[\frac{ \frac{ \cos \theta }{ \sin ^{2}\theta } }{ \frac{ 1 }{ \cos \theta }}\] further \[\frac{ \cos \theta }{ \sin ^{2}\theta }*\frac{ \cos \theta }{ 1 }

OpenStudy (anonymous):

Excuse me Harkirat, but I don't understand what you are saying with the whole \[\frac{ \frac{ 1 }{ . How do I interpret that?

OpenStudy (anonymous):

sorry, it did not come out right....\[\frac{ \cos \theta }{ \sin ^{2}\theta }*\frac{ \cos \theta }{ 1 }\] now resolve this to get your answer

OpenStudy (anonymous):

Going off of what @Harkirat said, we just need to calculate \[\frac{ \frac{ \cos(\theta) }{\sin ^{2}(\theta) }} { \frac{ 1 }{ \cos(\theta) } } = \frac{ \cos(\theta) }{\sin ^{2}(\theta) } \frac{ \cos(\theta) }{ 1 } = \frac{ \cos ^{2}(\theta) }{ \sin ^{2}(\theta) }\]

OpenStudy (anonymous):

Finally \[\frac{ \cos ^{2}\theta }{ \sin ^{2}\theta }=\left( \frac{ \cos \theta }{ \sin \theta } \right)^{2}=\cot ^{2}\]

OpenStudy (anonymous):

I'm confused

OpenStudy (anonymous):

what part confuses you???

OpenStudy (anonymous):

Do I have this right? |dw:1374179350798:dw|

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