Mathematics
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OpenStudy (anonymous):
PLEASE HELP!!! Solve Complex Numbers
√−112
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OpenStudy (anonymous):
help me
OpenStudy (anonymous):
Try splitting the \[\sqrt{-122}\] into 2 square roots, one involving \[\sqrt{-1}\] and one involving the square root of something else
OpenStudy (anonymous):
would the other one be \[\sqrt{122}\]
OpenStudy (anonymous):
There's no way to solve \[\sqrt{-122}\]
OpenStudy (anonymous):
although...
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OpenStudy (anonymous):
it invovles immaginary numbers
OpenStudy (anonymous):
you can do \[\sqrt{-1}* \sqrt{122}\]
OpenStudy (anonymous):
\[\sqrt{-1} = i\]
OpenStudy (anonymous):
what's the sqrt of 122?
OpenStudy (anonymous):
You are correct, the other square root would be
\[\sqrt{122}\] Try simplifying it now
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OpenStudy (anonymous):
\[11.0453 i\] is your answer
OpenStudy (anonymous):
its the squareroot 112 not 122
OpenStudy (anonymous):
Whoops, my apologies. Can \[\sqrt{112}\] be simplified any further?
OpenStudy (anonymous):
oh then it would be 10.58300524 i
OpenStudy (anonymous):
its
4\[\sqrt{7}\]
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OpenStudy (anonymous):
4 squareroot 7
OpenStudy (anonymous):
Looks good, don't forget the imaginary i :)
OpenStudy (anonymous):
do i multiply it by \[\sqrt{-1}\] or \[\sqrt{i}\]
OpenStudy (anonymous):
\[\sqrt{-1} = i\] so you'll want to multiply by i
OpenStudy (anonymous):
thank you