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Algebra 15 Online
OpenStudy (nptweezy):

I have no idea what any of this means i need help ASAP (Pic Included)

OpenStudy (anonymous):

what is it?

OpenStudy (nptweezy):

OpenStudy (nptweezy):

@Zacharymartin

OpenStudy (mary.rojas):

if I were doing this with NO HELP then I would go with b or d because B-thats where it starts to get confusing in the shown work OR D-it is right..somehow, sorry I could not help.good luck

OpenStudy (nptweezy):

@mary.rojas could you help with another question

OpenStudy (mary.rojas):

...maybe

OpenStudy (nptweezy):

OpenStudy (nptweezy):

@doulikepiecauseidont

OpenStudy (anonymous):

Ok, well when you have \[\Large 4\sqrt{50}=4\sqrt{25*2}=4\sqrt{25}\sqrt{2}=4*5\sqrt{2}=20\sqrt{2}\]

OpenStudy (mary.rojas):

the first attachment "idk2.jpg" i am clueless and the second attachment "confused.jpg" I would only go with A

OpenStudy (anonymous):

That's where they messed up, they multiplied the 4 by the 25 instead of taking the square root of 25, thats how they got that 100 but thats not correct, you have to first take the sqrt of whatever your simplifying (in this case the 25 and 4 which are perfect squares) and simplify them down to 5 and 2 which are the sqrt's respectively, and then multiply that to the numbers just like I did up there

OpenStudy (nptweezy):

@doulikepiecauseidont & @mary.rojas thank you

OpenStudy (mary.rojas):

your welcome good luck :)

OpenStudy (anonymous):

Oh, well i CAN TELL YOU THAT \[\sqrt[3]{2^{4}}=\sqrt[3]{2^{2}\times 2^{2}}\] and that means they have common radicals so they can be combined, but in case you forget on a test, 3 of them say fals and one of them says true, so that would also be a good tip

OpenStudy (anonymous):

And the second one doesn't have liek radicals so you know its D

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