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Mathematics 22 Online
OpenStudy (anonymous):

see pic to tell me if im correct(its gonna take me a min to get the pic up)

OpenStudy (anonymous):

\[\sqrt{27}+\sqrt{75}\] i know that \[\sqrt{9}=3 9*3=27\]

OpenStudy (anonymous):

What were you solving for?

OpenStudy (anonymous):

just to simplfy im trying to figure out 75 like i just did 27

OpenStudy (anonymous):

@AlwaystheBookworm

OpenStudy (johnweldon1993):

little typo there \[\sqrt{27} = \sqrt{9}\sqrt{3} = 3\sqrt{3}\] Right?

OpenStudy (anonymous):

Okay, yeah that makes a lot more sense @johnweldon1993

OpenStudy (johnweldon1993):

lol I just figured that's what she meant @AlwaystheBookworm And @GreenBeanDemphsey think again of perfect squares \[\large \sqrt{75} = \sqrt{?}\sqrt{?}\]

OpenStudy (johnweldon1993):

*Hint* 25 * 3 = 75 :)

OpenStudy (anonymous):

ha i was think but yea that's what i ment @AlwaystheBookworm so would it be \[25\sqrt{3}\]?

OpenStudy (johnweldon1993):

Not quite \[\sqrt{75} = \sqrt{25}\sqrt{3}\] simplify that...

OpenStudy (anonymous):

well 5*5=25 so how would i write that?

OpenStudy (johnweldon1993):

\[\sqrt{75} = \sqrt{25}\sqrt{3} = 5\sqrt{3}\] Right? the square root of 25 is 5...so it becomes 5√3

OpenStudy (anonymous):

\[8\sqrt{3}\] would this be the whole answer?

OpenStudy (johnweldon1993):

That would be the correct answer :)

OpenStudy (anonymous):

that you btw i wrote you a testamionl( btw again im not the best speller)

OpenStudy (johnweldon1993):

Thank you for that :)

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