Question

I WILL FAN
Choose the equation below that represents the line passing through the point (2, -5) with a slope of -3.

y = -3x - 13

y = -3x + 11

y = -3x + 13

y = -3x + 1

Answer 1

@anthonyc123 Hello??? Are you actually typing?

Answer 2

Do see which linear equation that this point works for, simply plus in the X and Y values for that point into each equation, and see if it holds true.

First of all, they are all in slope-intercept form. \[y=mx +b\] where m=slope. Since the slope needs to be -3, and all of these have the slope, you can't rule any of them out this way.

Option 1: \[y =-3x -13\] with point (2,-5) for (x,y)
\[(-5)=-3(2)-13\]
\[-5=-6-13 ?\]
\[-5=-19 ?\]
NO, this point is not a value for this linear equation.

Option 2: \[y =-3x +11\] with point (2,-5) for (x,y)
\[(-5)=-3(2)+11\]
\[-5=-6+11 ?\]
\[-5=5\]
NO, this point is not a value for this linear equation.

Option 3: \[y =-3x +13\] with point (2,-5) for (x,y)
\[(-5)=-3(2)+13 ?\]
\[-5=-6+13 ?\]
\[-5=7 ?\]
NO, this point is not a value for this linear equation.

Option 4: \[y =-3x +1\] with point (2,-5) for (x,y)
\[(-5)=3(2)+1 ?\]
\[-5=-6+1 ?\]
\[-5=-5 \]
YES, this point is in this linear equation.

Answer 3

@anthonyc123 Thank you so much!!!!!

Answer 4

MMhmm