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Mathematics 14 Online
OpenStudy (nptweezy):

ASAP Please solve this (pic included)

OpenStudy (nptweezy):

OpenStudy (nptweezy):

@mathstudent55

OpenStudy (anonymous):

can you tell me : \[a(b+c)=?\]

OpenStudy (jdoe0001):

\(\bf 2\sqrt{3}(\sqrt{2}+\sqrt{3}) \implies (2\sqrt{3} \times \sqrt{2})+(2\sqrt{3} \times \sqrt{3})\)

OpenStudy (nptweezy):

@jdoe0001 which one is it

OpenStudy (jdoe0001):

well, just multiply them, coefficient with coefficient, and same root with same root \(\bf a\sqrt{n} \times b\sqrt{m} \implies (a\times b)\sqrt{n\times m}\)

OpenStudy (nptweezy):

so its D right? @jdoe0001

OpenStudy (jdoe0001):

well, multiply them and you'll see what you'd get

OpenStudy (jdoe0001):

let's try the 1st set \(\bf (2\sqrt{3} \times \sqrt{2})\) what does that give you?

OpenStudy (nptweezy):

2√6

OpenStudy (nptweezy):

4+√7*5+√7

OpenStudy (nptweezy):

can you teach me how to break that down and multiply @jdoe0001

OpenStudy (jdoe0001):

well, \(\bf 2\sqrt{6}\) is correct, what about the 2nd set \(\bf (2\sqrt{3} \times \sqrt{3})\)

OpenStudy (nptweezy):

2√9 @jdoe0001

OpenStudy (nptweezy):

@mathstudent55

OpenStudy (jdoe0001):

the distribution is correct, all terms are right now on the simplification, the 2nd term is off \(\bf -40\sqrt{5}\color{red}{-20\sqrt{15}}+2\sqrt{3}+3\)

OpenStudy (jdoe0001):

that one comes from the simplification of \(\bf -5\sqrt{60}\\ \color{blue}{\text{factors of 60 are 2, 2, 3, 5, 1}\\\ 2\times 2\times 3\times 5\times 1 =60\\ 2^2\times 3\times 5\times 1 =60\\} -5\sqrt{2^2\times 3\times 5}\\ -5(2)\sqrt{3\times 5} \implies -10\sqrt{15}\)

OpenStudy (nptweezy):

@jdoe0001

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