Question

oko

Answer 1

since the zeros look to be integers, the discriminant should be a perfect square

Answer 2

it is a little hard to read, but it does say \((-7,0)\) and \((-3,0)\) right?

Answer 3

ok then the discriminant must be a perfect square
and since the zeros are not at the vertex, that means it is not 0
that leaves 16

Answer 4

nevermind, hat was stupid question :)

Answer 5

The discriminant has to do with one part of the quadratic equation @malehuman01

Answer 6

if the discriminant was \(-13\) there would be no zeros

Answer 7

if the discriminant was \(15\) there would be two irrational zeros

Answer 8

or wait was it you @amandasoto144 that asked about the discriminant?

Answer 9

and if the discriminant was 0 it would have the vertex on the \(x\) axis

Answer 10

so it must be the only perfect square there other than zero, which is 16, yes

Answer 11

yes but nevermind :)

Answer 12

in fact, given the information you have from the graph we could find the discriminant for sure, but that is not necessary in this case

Answer 13

no

Answer 14

in that one the vertex is the same as the zero, i.e. the vertex is on the \(x\) axis

Answer 15

that means there is only one zero

Answer 16

quadratic formula tells you the zeros are
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] and if this is only one number, it must be \(-\frac{b}{2a}\) and so \(b^2-4ac=0\)

Answer 17

in other words, if the vertex is on the \(x\) axis, meaning there is only one zero, the discriminant must be zero and the equation is in fact a perfect square, like say \(y=(x-3)^2\)

Answer 18

yes

Answer 19

yw