@satellite73 What is the surface area of a sphere with a radius of 30 m? A)900π m2 B)90,000π m2 C)3,600π m2 D)1,800π m https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/630568,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/surface_area_and_volume/mc101-1.jpg
\[S.A = 4 \pi r ^{2}\] Substitute and solve.
\[4(3.14)(30^2)=11304\]
No don't substitute pi just do it pi(4)(900) = ?
\[(4)(900)=600\]
No , what is 4 x 9 ?
i said 3600 for the answer but 4 time 9 is 36
\( SA_{sphere} = 4 \pi r^2 \) \( SA_{sphere} = 4 \pi (30 ~m)^2 \) \( SA_{sphere} = 4 \pi (900 ~m^2) \) \( SA_{sphere} = 3600 \pi ~m^2 \)
@mathstudent55 hello i appreciate you helping me
https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/630568,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/circles/mc073-1.jpg what is the length of AC
When two secants are drawn to a circle from a point outside the circle, the product of one secant and its external segment is equal to the product of the other secant and its external segment. |dw:1374259150804:dw|
honestly am still confused on this whole issue
this is what the problem is
\( BC \times AC = DC \times EC \)
\[BC * AC=DC *EC\]
Right. Now plug in the three numbers you know and solve for AC.
6*x=60=6x/6=60/6 10=x correct
can you help me with this problem please https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/630568,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/right_triangles_and_trigonometry/mc051-1.jpg
in triangle ABC ,AB=3 and AC=9 what M<B to the nearest degree
You are correct. This is how you write it: \(BC \times AC = DC \times EC\) \(6 \times AC = 5 \times 12\) \(6(AC) = 60 \) \(AC = 10\)
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