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Mathematics 6 Online
OpenStudy (anonymous):

@satellite73 What is the surface area of a sphere with a radius of 30 m? A)900π m2 B)90,000π m2 C)3,600π m2 D)1,800π m https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/630568,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/surface_area_and_volume/mc101-1.jpg

OpenStudy (anonymous):

\[S.A = 4 \pi r ^{2}\] Substitute and solve.

OpenStudy (anonymous):

\[4(3.14)(30^2)=11304\]

OpenStudy (anonymous):

No don't substitute pi just do it pi(4)(900) = ?

OpenStudy (anonymous):

\[(4)(900)=600\]

OpenStudy (anonymous):

No , what is 4 x 9 ?

OpenStudy (anonymous):

i said 3600 for the answer but 4 time 9 is 36

OpenStudy (mathstudent55):

\( SA_{sphere} = 4 \pi r^2 \) \( SA_{sphere} = 4 \pi (30 ~m)^2 \) \( SA_{sphere} = 4 \pi (900 ~m^2) \) \( SA_{sphere} = 3600 \pi ~m^2 \)

OpenStudy (anonymous):

@mathstudent55 hello i appreciate you helping me

OpenStudy (mathstudent55):

When two secants are drawn to a circle from a point outside the circle, the product of one secant and its external segment is equal to the product of the other secant and its external segment. |dw:1374259150804:dw|

OpenStudy (anonymous):

honestly am still confused on this whole issue

OpenStudy (anonymous):

this is what the problem is

OpenStudy (mathstudent55):

\( BC \times AC = DC \times EC \)

OpenStudy (anonymous):

\[BC * AC=DC *EC\]

OpenStudy (mathstudent55):

Right. Now plug in the three numbers you know and solve for AC.

OpenStudy (anonymous):

6*x=60=6x/6=60/6 10=x correct

OpenStudy (anonymous):

in triangle ABC ,AB=3 and AC=9 what M<B to the nearest degree

OpenStudy (mathstudent55):

You are correct. This is how you write it: \(BC \times AC = DC \times EC\) \(6 \times AC = 5 \times 12\) \(6(AC) = 60 \) \(AC = 10\)

OpenStudy (mathstudent55):

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