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Mathematics 7 Online
OpenStudy (anonymous):

mhmm

OpenStudy (swissgirl):

\(8 \sqrt{63x^5} \) Is it like this?

OpenStudy (swissgirl):

Ok So \( \sqrt{63} = \sqrt{9*7} \)

OpenStudy (swissgirl):

We know that \( \sqrt{9}=3\) Sooo \( \sqrt{63}= \sqrt{9*7}=3\sqrt{7}\)

OpenStudy (swissgirl):

Okkk but we didnt finish off the problem What is the answer?

OpenStudy (swissgirl):

Well is x in the squareroot or out? Is it the way you typed or the way I typed it?

OpenStudy (swissgirl):

Ok so we can write it out as \( \sqrt{63x^5}= \sqrt{9*7*x*x*x*x*x}=\sqrt{3^2*7*x^2*x^2*x}=3*x*x \sqrt{7*x}\) \(=3x^2\sqrt{7x}\)

OpenStudy (swissgirl):

Do you follow what I did?

OpenStudy (swissgirl):

Ok so basically I broke evrything down 63=7*9 x^5=x*x*x*x*x

OpenStudy (swissgirl):

Then I tried to make everything squared so 9=3^2 and we know that sqrt of any number squared is the number itself sooo \( \sqrt{3^2}=3\) and \(\sqrt{x^2}=x\)

OpenStudy (swissgirl):

Actually it didnt

OpenStudy (swissgirl):

ok but the final answer is \( 8*3x^2\sqrt{7x} = 24x^2\sqrt{7x}\)

OpenStudy (swissgirl):

Your Welcome :)

OpenStudy (swissgirl):

You're Welcome Bad grammar :)

OpenStudy (swissgirl):

yes :)

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