If m is directly proportional to r^3, and m=1/12 when r=1/2, what is the value of m when r=3/2?
@Directrix
@Directrix
mk=r^3 for some number k let m = 1/12 and r = 1/2 k/12 = 1/8 k = 12/8 = 3/4 so (3/4)m=r^3 let r = (3/2) (3/4)m = (3/2)^3 = 27/8 (3/4)m = 27/8 m = (4/3)(27/8) = 4(9/8) = 9/2
@zzr0ck3r Why would the initial equation not be the following: m=kr^3 for some number k I'm confused on that.
well its just a number so m=kr^3 would just be m(1/k) = r^3 just l = 1/k and we have ml=r^3
does direct proportion mean integer?
What about this: m* (1/k) =r^3 for some number k Would that be correct?
I think, but k is just a number so no reason to right 1/k. just call that k.
write*
Neither of your answers are on the answer choices
Plus, I don't know the answer
@sakigirl That's what mathematics is all about - getting answers not the first time around but sometime around. Cogitation is everything. :)
Haha, that's very true
woops mk=r^3 for some number k let m = 1/12 and r = 1/2 k/12 = 1/8 k = 12/8 = 3/2 NOT (3/4) so m(3/2) = r^3 let r = (3/2) m(3/2) = 27/8 m = (2/3)(27/8) = 2(9/8) = 9/4 is 9/4 a choice?
Yes!
if not try the other way lol m = k * r^3 let m = 1/12 and r = 1/2 1/12 = k * 1/8 k = 2/3 r = 3/2 m = (2/3)(27/8) = 9/4 so it does not matter if we do m = kr^3 or mk=r^3 @Directrix I guess that makes sense....I guess lol
Well, I started out this way: r^3 * 1/12 = m * (3/2)^3 (1/2)^3 * (1/12) = m * (3/2)^3 1/8 * 1/12 = m * 27/8 1/8 * 1/12 * 8/27 = m At that point, m went off track. I did not account for the constant of proportionality.
ahh
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