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What is the solution to the equation log 2 x - log 2 4 = 5 ?
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what is \[\log_{2} 4\] ?
well it's \[\log_{2} 2^2=2\log_22\]
\[2\log_22=2*1=2\]
so you have \[\log_2x-2=5\] so \[\log_2x=7\]
x = 2 x = 4 x = 32 x = 128
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\[\log_ab=c \rightarrow b=a^c\]
try to write down these numbers in the form \[2^n\]
for example
\[2^5=32\]
does it satisfy your equation?- no, because 5 is not equal to 7
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try to write down 128 in that form, can you do that?
2^7
yes
log2x=7 does 2^7 satisfy this equation?
using this formula you can check that: logab=c→b=a^c
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Great thanks! :)
yw :)
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