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Mathematics 7 Online
OpenStudy (anonymous):

Help find x.

OpenStudy (anonymous):

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ohh its getting into my mind

OpenStudy (anonymous):

ok

hero (hero):

Ugh, I messed up on one of the angles.

hero (hero):

But I'm already starting to see a problem with it. I'm going to see what @hartnn can do to help.

OpenStudy (anonymous):

ok

hartnn (hartnn):

ok, let the central point be O can you fin angle AOB ? use the fact that angles in a triangle add upto 180 degrees

OpenStudy (anonymous):

well because a triangle equals 180 degrees so 70 + 60 = 130 180 -130 = 50 degrees

hero (hero):

@hartnn, you don't have to say what it is, but I'm just curious to know...Have you already figured out what x equals using your own methods?

hartnn (hartnn):

correct! so, angle DOE also 50 degrees! because < DOE and < AOB are vertical angles now, i have a bit lengthy method, find angle ADO first, similarly find EOB do u know how to ?

hartnn (hartnn):

yeah....using the fact that interior angles in a quadrilater add upto 360 degrees

hero (hero):

I already know that, but that didn't really help. The angles are all different.

hartnn (hartnn):

let me do it on paper...

OpenStudy (anonymous):

50 + x = 180 x = 130 degrees <AOB

OpenStudy (anonymous):

and for DOE has to be 40 degrees

OpenStudy (anonymous):

am I right?

OpenStudy (anonymous):

ohh ok I might be able to do the question by my self I know how to do it from here thaks @hartnn and @Hero

hero (hero):

@hartnn, did you set up a system of equations to solve it?

hartnn (hartnn):

yeah, i used angle C too.... the angle BDE was giving trouble, but i think we get 2 equation and 2 unknown angle BDE and x

OpenStudy (anonymous):

I got 20 degrees for the answer tell me if im right?

OpenStudy (anonymous):

i can explain.

hartnn (hartnn):

sure, go ahead

OpenStudy (anonymous):

ok first you remember that we got 130 degrees for <AOB right so because angle DOE is a supplementary angle it should be 180 - 130 = 50 degrees am i right?

hartnn (hartnn):

yes

OpenStudy (anonymous):

then you can find the answer <DEO = 30+x = (180-80)/2 = 50 so x = 20 degrees

hartnn (hartnn):

sorry, didn't get you...

hero (hero):

@hartnn, I already tried using the quadrilateral sum of angles rule. I got nowhere bro.

hero (hero):

Like I said, I tried setting up a system of equations. But it didn't work

hartnn (hartnn):

yeah, i got 2 equation, when simplified they were exactly same :P

hero (hero):

Yep, same thing happened to me. So you haven't solved it yet. Good. At least we're on the same page.

hero (hero):

When I said I ran into a problem earlier, this is what I was talking about.

hartnn (hartnn):

there should be more info given.....?

OpenStudy (anonymous):

its hard right?

hero (hero):

I wouldn't use "hard" to describe this problem

OpenStudy (anonymous):

wait lets do this then we have this figure right? |dw:1374239367170:dw|

OpenStudy (anonymous):

lets make more lines like this

OpenStudy (anonymous):

|dw:1374239526486:dw|

hartnn (hartnn):

|dw:1374243151883:dw| thats all we know yet...

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