Question

The figures above are similar. Find the missing length. Show your work.

Answer 1

i got this far and then got stuck so if anyone could help?!?!?!



Length of the first rectangle = L1

Width of the first rectangle = W1

Length of second rectangle = L2

width of the second rectangle = W2

L1/W1=L2/W2

Answer 2

yes. now replace the letters (variables) with the numbers they give you in the problem.

can you do that ?

Answer 3

i dont understand

Answer 4

you say

Length of the first rectangle = L1


what is the length of the first rectangle ?

Answer 5

1?

Answer 6

wait is it 2?

Answer 7

are you looking at

Answer 8

and the 2nd square four?

Answer 9

im sorry im so bad at math

Answer 10

I see

Answer 11

yes

Answer 12

one of the sides is called the "length"
normally the longer side

what is length of the first figure ?

Answer 13

5

Answer 14

that means in

L1/W1=L2/W2

replace the L1 (length of the first figure) with 5, like this
5/W1 = L2/W2

what is the width of the first figure ? (the width is the side that is not the length)

Answer 15

Length of the first rectangle = L5

Width of the first rectangle = W3

Length of second rectangle = L3

width of the second rectangle = W2

?

Answer 16

yes, but without the letters. Just use the numbers

you get
Length of the first rectangle = 5

Width of the first rectangle = 3

Length of second rectangle = 3

the width of the 2nd figure is not a number. It is x (for "unknown")

width of the second rectangle =x

now use those in your equation
L1/W1=L2/W2

can you replace L1 with 5 and W1 with 3 and L2 with 3 and W2 with x ?

Answer 17

Length of the first rectangle = 5

Width of the first rectangle = 3

Length of second rectangle = 3

width of the second rectangle = x

L1/W1=L2/W2

Answer 18

?

Answer 19

yes, but use the numbers in
L1/W1=L2/W2

Answer 20

ok so


Length of the first rectangle = 5

Width of the first rectangle = 3

Length of second rectangle = 3

width of the second rectangle = x

3/5=3/x

Answer 21

yes. except you have to be careful. the length of the 2nd figure is 3 (not x)
so it should be
\[ \frac{3}{5}= \frac{x}{3} \]

to find x, multiply both sides by 3. can you do that ?

Answer 22

in fact you should do it this way:
L1/W1=L2/W2

L1 is 5 and W1 is 3 so it should be
5/3 = L2/W2

L2 is 3 and W2 is x, so it is
5/3 = 3/x

to find x, you can cross multiply
5x = 9
then divide by 5
x= 9/5

Answer 23

Length of the first rectangle = 5

Width of the first rectangle = 3

Length of second rectangle = 3

width of the second rectangle = x

5/3=3/2???????

Answer 24

yes, except it is x not 2:

5/3=3/x

Answer 25

im confused and i know its probably so easy

Answer 26

Do you get the idea that you replace the "variables" L1, W1 , L2 and W2 with the numbers and the x ?

Answer 27

ok so this is right?


Length of the first rectangle = 5

Width of the first rectangle = 3

Length of second rectangle = 3

width of the second rectangle = x

5/3=3/x

Answer 28

yes, that looks good.

now you have to "solve" for x

do you know how to "cross multiply" ?

Answer 29

kindve

Answer 30

but i have to go pick my son up from camp so i will be right back hopevully ur still on

Answer 31

just send a message when you are back

Answer 32

okie dokie im back

Answer 33

you have
\[ \frac{5}{3}=\frac{3}{x} \]
cross multiply uses this rule:
\[ \frac{a}{b} =\frac{c}{d} \\ad=bc \]
you multiply the top left times the bottom right
and set that equal to bottom left times top right

use that rule for
\[ \frac{5}{3}=\frac{3}{x} \]

Answer 34

5/3=3/10 ?