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Mathematics 8 Online
OpenStudy (anonymous):

√(x+2)+4=x

OpenStudy (anonymous):

i know it would turn to x+2=x-4 but idk what to do next

OpenStudy (anonymous):

is this sqrt sign applicable to all terms?

OpenStudy (anonymous):

only to the parenthesis like \[\sqrt{x+2}+4=x\]

OpenStudy (anonymous):

oh..okay

OpenStudy (anonymous):

so after x+2=x-4 what do i need to do?

OpenStudy (anonymous):

how did you got x+2=x-4?

OpenStudy (anonymous):

i squared the one side and honestly i dont know how i came up with the x-4 i guess i just moved the 4 to the other side and changed signs

OpenStudy (anonymous):

no no no...

OpenStudy (anonymous):

I have the answer will you listen?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

you got root(x+2)=x-4

hartnn (hartnn):

you mean \(\sqrt{x+2} = x-4 \) now square both sides. and for, \((x-4)^2\) use the formula \((a-b)^2=a^2-2ab+b^2\)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

isnt it?

OpenStudy (anonymous):

yeah i was agreeing

OpenStudy (anonymous):

square both sides

OpenStudy (anonymous):

x+2=x-4^2

OpenStudy (anonymous):

x+2=x^2-8x+16

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

(a-b)^2=a^2-2ab+b^2

OpenStudy (anonymous):

thats confusing

OpenStudy (anonymous):

that is the expansion of (a-b)^2

OpenStudy (anonymous):

ooh ok i got it now after looking at it for a bit

OpenStudy (anonymous):

(x-4)^x^2-(2*x*4)+4^2

OpenStudy (anonymous):

k..

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

x+2 to the RHS

OpenStudy (anonymous):

RHS?

OpenStudy (anonymous):

right side?

OpenStudy (anonymous):

0=\[x^2-8x+16-x-2\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Right Hand Side=RHS

OpenStudy (anonymous):

ive never seen any one abbreviate that before

OpenStudy (anonymous):

0=\[x^2-9x+14\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

now do you know how to factorize?

OpenStudy (anonymous):

can you give me an example? im not sure

OpenStudy (anonymous):

or the formula for qudriatic equations?

OpenStudy (anonymous):

ok i will give an example of factorizing..

OpenStudy (anonymous):

x^2+3x+2 can be factorized as (x+1)(x+3)

OpenStudy (anonymous):

yeah x=\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

OpenStudy (anonymous):

cool...use it now

OpenStudy (anonymous):

you need to understand how to factorize for doing this faster

OpenStudy (anonymous):

got the answer?7 or 2

OpenStudy (anonymous):

i got 7

OpenStudy (anonymous):

or 2

OpenStudy (anonymous):

its plus or minus

OpenStudy (anonymous):

yeah i got that sorry

OpenStudy (anonymous):

you need to know hw to factorize..I will show you how this should be done here

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

here you have x^2-9x+14

OpenStudy (anonymous):

which two numbers give 14 when multiplied and gives (-9) when added?

OpenStudy (anonymous):

-7 and +2

OpenStudy (anonymous):

-7 and -2

OpenStudy (anonymous):

oh right

OpenStudy (anonymous):

so the factorized form is (x-7)*(x-2)=0

OpenStudy (anonymous):

so for this to be zero either x=7 or x=2..

OpenStudy (anonymous):

you got it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you i actually knew that i just forgot over summer

OpenStudy (anonymous):

hahaha..Happens to me often..I get blank after summer:)

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