Question

solve the rational equation \[\[\frac{ m }{ 6 }-\frac{ 5 }{ 3 }=\frac{ 15 }{ m^2-25}\] \]

Answer 1

under the 15 should be m+5 m_5

Answer 2

$$\bf
\frac{ m }{ 6 }-\frac{ 5 }{ 3 }=\frac{ 15 }{ m^2-25}\\
\frac{m-10}{6} = \frac{ 15 }{ m^2-25}
$$

then just cross multiply

Answer 3

I get \(\bf m^3-10m^2-25m-250=80\\
m^3-10m^2-25m-330 = 0\)

Answer 4

My first comment was wrong

Answer 5

\(\bf \cfrac{ m }{ 6 }-\cfrac{ 5 }{ 3 }=\cfrac{ 15 }{ (m+5)(m-5)}\ \ ?\)

Answer 6

no I mixed two problems up on accident \[\frac{ m }{ 6 }-\frac{ 5 }{ 3 }=\frac{ x+2 }{ 3}\]

Answer 7

Thats the real problem^^

Answer 8

same thing \(\bf \large \cfrac{ m }{ 6 }-\cfrac{ 5 }{ 3 }=\cfrac{ x+2 }{ 3}\\
\cfrac{m-10}{6} = \cfrac{ x+2 }{ 3}\)
then cross multiply

Answer 9

6x-3m +32 = 0 is what I get

Answer 10

erk

Answer 11

6x-3m +42 = 0 is what I get

Answer 12

oh okay thanks :)

Answer 13

yw