Question

Perform the indicated operation. Simplify if possible. \frac{ x^2-6x }{x-2}+\frac{ 8 }{ x-2 }

Answer 1

\[\frac{ x ^{2}-6x }{ x-2 }+\frac{ 8 }{ x-2 }=\frac{ x ^{2}-6x+8 }{ x-2 }\]
-6=-4-2
-4*-2=8
1*8=8
factorise the numerators and denominators and cancel the common factor.

Answer 2

?

Answer 3

\[\frac{ x ^{2}-4x-2x+8 }{ x-2}=\frac{ x \left( x-4 \right)-2\left( x-4 \right) }{ x-2 }\]
\[=\frac{ \left( x-2 \right)\left( x-4 \right) }{x-2 }\]
=x-4

Answer 4

thanks I was confused