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Mathematics 6 Online
OpenStudy (anonymous):

Please help on this geometry question??? (Surface area of a pyramid)

OpenStudy (anonymous):

OpenStudy (jdoe0001):

can you find the "purple side" in that triangle using the pythagorean theorem?

OpenStudy (anonymous):

17?

OpenStudy (jdoe0001):

yes now let's look at that triangle, the one facing out, like |dw:1374257994069:dw|

OpenStudy (jdoe0001):

bear in mind that the pyramid, has a SQUARE bottom, or square base, is a 16x16 square and we know that area of that and it has 4 TRIANGLES like the one above, sitting on top of the square at the edges so, you get the area for that triangle, add it 4 times, PLUS the area of the squarish bottom and that's the surface area of the pyramid :)

OpenStudy (anonymous):

800?

OpenStudy (jdoe0001):

yes

OpenStudy (anonymous):

Thanks! :) Do you think you could help me on another problem kind of like this one?

OpenStudy (anonymous):

OpenStudy (jdoe0001):

lateral area of a cone is => \(\bf \large \pi r \sqrt{r^2+h^2}\) h = height, or altitude, in this case 22m r = radius of base, in this case 14m

OpenStudy (anonymous):

I keep getting 365 pi, but it's not an option..

OpenStudy (jdoe0001):

hmmm, maybe I got the total surface.... try this one http://www.mathwarehouse.com/solid-geometry/cone/images/surface-area-of-cone/lateral-surface-area-formula-picture.jpg that is \(\bf \large \pi r h\)

OpenStudy (anonymous):

308, and that's an option. Thanks! :)

OpenStudy (jdoe0001):

yw

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