What is the slope of the line passing through the point (4, −2) and perpendicular to the line y = 4x + 2? Write your answer as a fraction.
what's the slope of => y = 4x + 2 ?
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oh yeah so what am i suppose to do with that.
get the slope of that equation first :)
can I have the slope equation please.
\(\bf m=\frac{y_2-y_1}{x_2-x_1}\) but you don't have 2 points on this 1st equation, you only have the equation
so you'd need to get it from the equation => y = 4x + 2
but what am I suppose to do when they only give me one set points
we'll get there, but firstly we know this -> y = 4x + 2 <- line is perpendicular to the other at (4, -2) so, let's get the slope for this one 1st, so we can see if we can find the other :)
???
http://www.algebra-class.com/image-files/slope-formula-1.gif can you find the slope from ^ picture?
Im really unsure
y = ax + b y = 4x + 2 \( y = \color{red}{4}x + 2\) see it now?
To find the slope of a line when you're given the equation of the perpendicular line, you take the slope, turn it upside down, then change the sign. So y = 4x + 2 has a slope of 4 --> turn it upside down = 1/4, change the sign --> -1/4. Therefore the slope of the second line is -1/4.
yes
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