Quadrilateral ABCD with vertices at A(-5,-1),B (2,4),C (9, 2), and D (2,-3) is shown. Diagonal BD is drawn. Use coordinate geometry to prove that angels ABD=CDB.
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...it looks like that
Good drawing!
The first thing is your points need to have two numbers each. Coordinate pairs have an x value and a y value (x,y).
well ya they do in the question :)
Right, your drawing should have that information too. What are the numbers in your drawing?
Ahem, diagram*.
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Good.
-5-1 lol I messed up on the picture xp
That's okay, just remember it's (-5, -1) for the calculation.
Okay, next question, what is the distance formula?
lol I thought you were just going to give me the answer so its not long and confusing XD
Use the distance formula to find the length of AB, BC, BD, CD, and AD.
Distance Formula \[distance = \sqrt{(x _{1} - x _{2})^{2} + (y _{1} - y _{2})^{2}}\]
Lets find AB together using the distance formula.
3.4?
8.6!?
\[AB = \sqrt{(-5 - 2)^{2} + (-1 - 4)^{2}}\] \[AB = \sqrt{(-7)^{2} + (-5)^{2}}\] \[AB = \sqrt{49 + 25}\] \[AB = \sqrt{74}\]
ya 8.6 lol
Great!
Okay, now use the distance formula to find BC, CD, AD, and BD.
ok now the whoe final answer all together is what lmao =p
whole
This is a proof problem that requires multiple steps. Thank you for being so patient with this.
Okay, find BC using the distance formula.
lol 7.2
BC = sqrt( (2 - 9)^2 + (4 - 2)^2) BC = sqrt( (-7)^2 + (-2)^2) BC = sqrt( 49 + 4) BC = sqrt(54) BC = 3 * sqrt(6)
hmmm, I'm getting 7.34.
Can you show me any of the work that you are doing to get your answers?
What was the number under the square root?
Ah, I found my mistake.
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