Mathematics
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OpenStudy (anonymous):
The length of a diagonal of a square is 7 inches. Find the perimeter of the square.
A. 25 inches
B. 12 inches
C. 19.6 inches
D. 28 inches
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OpenStudy (goldphenoix):
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OpenStudy (goldphenoix):
Do you know how to set up the equation?
OpenStudy (anonymous):
2a^2=7^2
OpenStudy (goldphenoix):
Not quite. You're missing b.
So the equation would look like: \[\large \large a^2 + b^2 = 7^2\]
OpenStudy (goldphenoix):
Now simplify. What would 7^2 become?
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OpenStudy (anonymous):
49
OpenStudy (goldphenoix):
So it would look like: \[\large \large a^2 + b^2 = 49\]
OpenStudy (goldphenoix):
Since its a square, you can write it as: \[\large \large a^2 + a^2 = 49\] Now what does
a^2 + a^2 give us?
OpenStudy (anonymous):
2a^2.
OpenStudy (anonymous):
@RPguy @eSpeX
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OpenStudy (espex):
You have worked your equation down to \(2a^2=49\), isolate your \(a^2\) next.
OpenStudy (espex):
How would you get your \(a^2\) alone?
OpenStudy (anonymous):
\[\sqrt{a}^{2}=\sqrt{49}\]
OpenStudy (espex):
Close, but recall that you have \(2a^2\), so you will need to divide out the 2 before you can take the square root and get 'a'.
OpenStudy (anonymous):
\[\sqrt{24.5}=\sqrt{a}^{2}\]
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OpenStudy (espex):
Yes, making 'a' equal to ?
OpenStudy (espex):
And then you know that the perimeter of a square is equal to \(4a\)
OpenStudy (anonymous):
so it will be c
OpenStudy (espex):
Yes, nice work. :)
OpenStudy (anonymous):
thank you :)
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OpenStudy (espex):
You're welcome.