Which of the following is not an equivalent form of the compound inequality x - 1 10 x -2 A number line with an open circle on -11, shading to the left, and an open circle on -2, shading to the right. A number line with an open circle on -11, an open circle on -2, and shading in between. x -2 or x

Question

Which of the following is not an equivalent form of the compound inequality x - 1 < -12 or x + 12 > 10 x < -11 or x > -2 A number line with an open circle on -11, shading to the left, and an open circle on -2, shading to the right. A number line with an open circle on -11, an open circle on -2, and shading in between. x > -2 or x < -11

whpalmer4 · Answer

$$x-1<-12$$Add 1 to both sides $$x < -12+1$$$$x<-11$$ $$x+12>10$$subtract 12 from both sides $$x>10-12$$$$x>-2$$ So $x < -11$ or $x > -2$ are our two "cleaned-up" inequalities. If we plot them on the number line, we'll have open circles (because there is no equals component). If we try the point $x=0$, that satisfies the inequality, so we'll shade the line segments outside the circles because $x=0$ is outside the circles. |dw:1374282724785:dw|

whpalmer4 · Answer

You should be able to look at your answer choices and see which one doesn't reflect the diagram and inequalities.