Question

(b+3)-c(b+3) in factor form ??

Answer 1

In factored form or simplified form because it already seems like it's expanded

Answer 2

simplified cause i think the answer is (-c) (b+3)

Answer 3

Consider your first term as \(1(b+3)\) and then look for a common factor in both terms.

Answer 4

so -c turns into 1

Answer 5

It should be (1-c)(b+3) I believe

Answer 6

As eSpeX said, there is a 1 in front of the first (b+3). Therefore giving you
1(b+3) - c(b+3). Since both have (b+3), you can combine the outer numbers and multiply what has multiplicity as such:
(1-c)(b+3)

Answer 7

thanks