Question

I WILL FAN AND MEDAL!
Find the product of (3x + 7y)(3x − 7y).

9x2 − 42xy + 49y2

9x2 + 42xy + 49y2

9x2 − 49y2

9x2 + 49y2

Answer 1

cant go farther than that

Answer 2

Do you know foil?

Answer 3

Get rid of the squares

Answer 4

cant solve it any more

Answer 5

\[\large (a+b)(a-b)=a^2-b^2\] with
\[a=3x,b=7y\]

Answer 6

You cant get rid of them bcus they have to be the same variables

Answer 7

All of the 2's are exponets and @domu i do not know foil

Answer 8

\[(x+a)(x-a) = x^2 - a^2 \]

Answer 9

as usual it is C because it is always C
every time it is C
never A or B
once in a while D well, not too often

Answer 10

I'm sorry guys im not understanding where the a's and b's are coming from :(

Answer 11

[9x^{2}-49y ^{2}\] is correct by using formula

Answer 12

(3x + 7y)(3x − 7y)

3x * 3x = 9x^2
3x * -7y = -21xy

7y * 3x = +21xy
7y * -7y = -49y

9x^2 -21xy + 21xy - 49y

9x^2 - 49y

Answer 13

@SOS101

Answer 14

Thank You all!

Answer 15

yw

Answer 16

did i mention is was C?

Answer 17

LOL @satellite73 yes u did Sir

Answer 18

so long method of @some_someone

Answer 19

the \(a\) and \(b\) are general
it is always the case that \[(a+b)(a-b)=a^2-b^2\] and so
\[(3x+7y)(3x-7y)=(3x)^2-(7y)^2=9x^2-49y^2\]

Answer 20

Lol im sorry satellite I was trying to give the person with less points a medal, Sorry for the inconvience im laughing so hard at satellite's comment

Answer 21

I will get my sister to give u a medal @satellite73

Answer 22

7y*7y=49y^2?????

Answer 23

i have plenty, thank you though
and my sincere apologies to all who found my post abusive ...

Answer 24

@rashad.dawkins do you have a question?

Answer 25

Lol No @satellite73 Not abusive ; just really had me crackin up

Answer 26

I thought 7y^2 times itself is 49 squared?