Find the value of x. http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/a/assessments/Semester1Exam/Geometry_SemesterA_Final_282q.gif
same dash on a side means they're equal
30x+11y = 12 ---------(1) 2x_+3y = 12 ----------(2)
yah i know that. and all the angles put together =180. i see all the peices of the puzzle. i just need help putting them togthr
two equations, two uknowns you can solve them
dont look at angles, we dont need them here
30x+11y = 12 ---------(1) 2x +3y = 12 ----------(2)
i really dont know how to solve them. i dont know how to solve that when there are TWO variables
wait a sec, we may be interpretting hte problem incorrectly
im sorry :( i really dont know how to approach this problem
no it seems like thats what ur supposedd to do. i just dont know how. when there are two different variables
is it given that the diagram is a trap ?
I think the equations are \[2x+3y = 12\] (because the sides are congruent) \[112 = 30x+11y\] (because the angles are congruent)
that assumes diagram is a trap
so then the answer would be...
you didnt answer whether its a trap or not
well, it isn't reasonable that 2x+3y and 30x+11y both equal 12 unless one of them is negative
i dont know if its a trap
i didnt get that, but it makes no sense to assume its a trap, if its not given
I assume that it is a trapezoid. agreed that it could be clearer...
yeah watever still you need to solve 2 equations, good luck !
the angle is of no relevance if not a trapezoid...
its multiple voice. the available options are: A.3 B.2 C.12 D.6
that help?
the answer is there if it is a trapezoid.
and not if we solve the "not a trapezoid" equations.
you can see the pic
solve the equations I provided and you'll get an answer you can select... Solve the other equations and you'll get \(x = \dfrac{96}{13}, y = -\dfrac{12}{13}\)
dude im so lost. i hate to be this way, but ur gonna have to tell me the answer. and then how you got it
cuz i really just dont know how :/
No, I don't have to do any such thing. I'll help you figure it out, though. \[2x+3y=12\] (because the sides are congruent) \[30x+11y=112\] (because the angles are congruent) Multiply the first equation by -15 so that when we add the two equations together, the \(x\) terms will cancel each other out and leave us an equation just in terms of \(y\).
Do that, add them together, tell me what you get.
i got 12
You got 12 when you multiplied the first equation by -15 and added the two equations together? What happened to \(y\)?
thats what i got... i dont know
Try it again. If you get 12 again, show me your work.
What is -15 * the first equation? You should have a term with \(x\), a term with \(y\), an equals sign, and a number
oh!! its 2!!
what is 2?
the answer!! x
no...
what!?
careful and correct wins the day here...you're jumping all over the place and making mistakes. -15* first equation is \[-15*2x - 15*3y=-15*12\] \[-30x -45 y = -180\]Add that to the other equation: \[30x+11y =112\]-------------------------- \[(30x-30x) + (11y-45y) = 112-180\]\[-34y = -68\]\[y=2\] Now plug that value into either of the original equations and solve for \(x\)
omg............ its 3
thank you!
Bingo!
thank you. i would give you a thousanf medals if i could!
Now, let's check the answer: 2(3)+3(2) = 6+6 = 12 our sides match 30(3)+11(2) = 90 + 22 = 112 our angles match
1 medal and you working carefully to get the right answer in the future is all I ask :-)
any questions about what we did?
no. it make sense. thank you so much!
that's what I like to hear!
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