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Mathematics 11 Online
OpenStudy (anonymous):

Find the value of x. http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/a/assessments/Semester1Exam/Geometry_SemesterA_Final_282q.gif

ganeshie8 (ganeshie8):

same dash on a side means they're equal

ganeshie8 (ganeshie8):

30x+11y = 12 ---------(1) 2x_+3y = 12 ----------(2)

OpenStudy (anonymous):

yah i know that. and all the angles put together =180. i see all the peices of the puzzle. i just need help putting them togthr

ganeshie8 (ganeshie8):

two equations, two uknowns you can solve them

ganeshie8 (ganeshie8):

dont look at angles, we dont need them here

ganeshie8 (ganeshie8):

30x+11y = 12 ---------(1) 2x +3y = 12 ----------(2)

OpenStudy (anonymous):

i really dont know how to solve them. i dont know how to solve that when there are TWO variables

ganeshie8 (ganeshie8):

wait a sec, we may be interpretting hte problem incorrectly

OpenStudy (anonymous):

im sorry :( i really dont know how to approach this problem

OpenStudy (anonymous):

no it seems like thats what ur supposedd to do. i just dont know how. when there are two different variables

ganeshie8 (ganeshie8):

is it given that the diagram is a trap ?

OpenStudy (whpalmer4):

I think the equations are \[2x+3y = 12\] (because the sides are congruent) \[112 = 30x+11y\] (because the angles are congruent)

ganeshie8 (ganeshie8):

that assumes diagram is a trap

OpenStudy (anonymous):

so then the answer would be...

ganeshie8 (ganeshie8):

you didnt answer whether its a trap or not

OpenStudy (whpalmer4):

well, it isn't reasonable that 2x+3y and 30x+11y both equal 12 unless one of them is negative

OpenStudy (anonymous):

i dont know if its a trap

ganeshie8 (ganeshie8):

i didnt get that, but it makes no sense to assume its a trap, if its not given

OpenStudy (whpalmer4):

I assume that it is a trapezoid. agreed that it could be clearer...

ganeshie8 (ganeshie8):

yeah watever still you need to solve 2 equations, good luck !

OpenStudy (whpalmer4):

the angle is of no relevance if not a trapezoid...

OpenStudy (anonymous):

its multiple voice. the available options are: A.3 B.2 C.12 D.6

OpenStudy (anonymous):

that help?

OpenStudy (whpalmer4):

the answer is there if it is a trapezoid.

OpenStudy (whpalmer4):

and not if we solve the "not a trapezoid" equations.

OpenStudy (anonymous):

you can see the pic

OpenStudy (whpalmer4):

solve the equations I provided and you'll get an answer you can select... Solve the other equations and you'll get \(x = \dfrac{96}{13}, y = -\dfrac{12}{13}\)

OpenStudy (anonymous):

dude im so lost. i hate to be this way, but ur gonna have to tell me the answer. and then how you got it

OpenStudy (anonymous):

cuz i really just dont know how :/

OpenStudy (whpalmer4):

No, I don't have to do any such thing. I'll help you figure it out, though. \[2x+3y=12\] (because the sides are congruent) \[30x+11y=112\] (because the angles are congruent) Multiply the first equation by -15 so that when we add the two equations together, the \(x\) terms will cancel each other out and leave us an equation just in terms of \(y\).

OpenStudy (whpalmer4):

Do that, add them together, tell me what you get.

OpenStudy (anonymous):

i got 12

OpenStudy (whpalmer4):

You got 12 when you multiplied the first equation by -15 and added the two equations together? What happened to \(y\)?

OpenStudy (anonymous):

thats what i got... i dont know

OpenStudy (whpalmer4):

Try it again. If you get 12 again, show me your work.

OpenStudy (whpalmer4):

What is -15 * the first equation? You should have a term with \(x\), a term with \(y\), an equals sign, and a number

OpenStudy (anonymous):

oh!! its 2!!

OpenStudy (whpalmer4):

what is 2?

OpenStudy (anonymous):

the answer!! x

OpenStudy (whpalmer4):

no...

OpenStudy (anonymous):

what!?

OpenStudy (whpalmer4):

careful and correct wins the day here...you're jumping all over the place and making mistakes. -15* first equation is \[-15*2x - 15*3y=-15*12\] \[-30x -45 y = -180\]Add that to the other equation: \[30x+11y =112\]-------------------------- \[(30x-30x) + (11y-45y) = 112-180\]\[-34y = -68\]\[y=2\] Now plug that value into either of the original equations and solve for \(x\)

OpenStudy (anonymous):

omg............ its 3

OpenStudy (anonymous):

thank you!

OpenStudy (whpalmer4):

Bingo!

OpenStudy (anonymous):

thank you. i would give you a thousanf medals if i could!

OpenStudy (whpalmer4):

Now, let's check the answer: 2(3)+3(2) = 6+6 = 12 our sides match 30(3)+11(2) = 90 + 22 = 112 our angles match

OpenStudy (whpalmer4):

1 medal and you working carefully to get the right answer in the future is all I ask :-)

OpenStudy (whpalmer4):

any questions about what we did?

OpenStudy (anonymous):

no. it make sense. thank you so much!

OpenStudy (whpalmer4):

that's what I like to hear!

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