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Simplify completely: the quantity 6 times x to the 4th power plus 9 times x to the 2nd power plus 12 times x all over 3 times x
2x3 + 9x2 + 12
2x2 + 3x + 4
2x5 + 3x3 + 4x2
2x3 + 3x + 4
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HanAkoSolo (jamierox4ev3r):
6x^4+9x^2+12x/3x
HanAkoSolo (jamierox4ev3r):
then you would use 3x to divide all of the integers in the numerator by the quantity of 3x
(ex: 12x/3x=4)
OpenStudy (anonymous):
But i think whats confusing me is the exponents i dont know what to do with them @Jamierox4ev3r
HanAkoSolo (jamierox4ev3r):
hint: 9x^2 divided by 3x= 3x
HanAkoSolo (jamierox4ev3r):
based from that, can you figure out the rest?
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HanAkoSolo (jamierox4ev3r):
@HelloGoodmorning
OpenStudy (anonymous):
But what about the exponent @Jamierox4ev3r
HanAkoSolo (jamierox4ev3r):
6^4/3x=2x^3
OpenStudy (anonymous):
Ok so did you subtract the exponent like 6^4/3^1=2^3
OpenStudy (anonymous):
@Jamierox4ev3r
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HanAkoSolo (jamierox4ev3r):
well, when you divide, one exponenent is automatically cancelled out