help with series
\[\sum_{0}^{\infty} C _{n} X ^{n}\] Cn+4=Cn for all n>=0 find interval of convergence and formula for F(x)
\[C _{n+4}=C _{n}\]
i am afraid this does not make much sense saying \(C_n=C_{n+4}\) just tells you every fourth coefficient is the same not nearly enough information
Nothing more give. I thing this question should be solved in terms of C.
there must be something missing for example \(C_k=10 \) for all \(k\) would fit that bill, so would \(C_1=1, C_2=2, C_3=3, C_4=4, C_5-1, C_6=2, ...\)
No nothing at all i check it.
\[F(x) = 1/(1-x ^{4}) (C _{0} + C _{1}x+C _{2}x ^{2}+C _{3}x ^{3})\] Which converges for x≠1,x≠−1,x≠i,x≠−i
The attack goes like this ...
\[C _{0}+C _{1}x+C _{2}x ^{2}+C _{3}x ^{3}+C _{0}x ^{4}+ C _{1}x ^{5}+C _{2}x ^{6}+C _{3}x ^{7}+C _{0}x ^{8}+C _{1}x ^{9}+C _{2}x ^{10}+C _{3}x ^{11}\] \[=C _{0}\sum_{n=0}^{\infty}x ^{4n}+C _{1}x \sum_{n=0}^{\infty}x ^{4n}+C _{2}x ^{2} \sum_{n=0}^{\infty}x ^{4n}+C _{3}x ^{3} \sum_{n=0}^{\infty}x ^{4n}+\] \[= (C _{0}+C _{1}x+C _{2}x ^{2}+C _{3}x ^{3}) \sum_{n=0}^{\infty}x ^{4n}\] \[[= (C _{0}+C _{1}x+C _{2}x ^{2}+C _{3}x ^{3}) (1/(1-x ^{4})\] That's it!
Correction: |x| < 1 is the region of convergence.
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