Please help I do not understand I will give a medal
The diameter of a circle drawn on a coordinate grid has one of its end points at (-3, 2) and the other end point at (6, -4). Leena performed the steps shown to find the length of the diameter. Step 1. x1 = -3, y1 = 2, x2 = 6, y2 = -4 Step 2. Distance = Distance is equal to the square root of all of x2 minus x1 the whole square minus y2 minus y1 the whole square. Step 3. Distance = Distance is equal to the square root of all of 6 plus 3 the whole square minus -4 minus 2 the whole square. Step 4. Distance = Distance is equal to the square root of all of 9 square minus -6 the whole square. Step 5. Distance is approximately 6.71 In which step did Leena first make an error? Step 1, because she substituted the incorrect values for x2 and y1. Step 3, because she added the x coordinates instead of subtracting them. Step 2, because she used the incorrect formula to find the length. Step 5, because she found the square root of 45 instead of the square root of 9.
so, do you know the distance formula?
no :C
ok well :/ \(\bf \text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)
so the first step is wrong?
I see nothing wrong with 1 let's check 2, see anything wrong?
i dont really know
well, let's take a look at 2 Step 2. Distance = Distance is equal to the square root of all of x2 minus x1 the whole square minus y2 minus y1 the whole square.
so it is B cuz i have to submit this in 1 min lol
heehe
?
lemme show you the formula again => \(\text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\) lemme show you the 2nd step \(\text{Step 2. Distance = Distance is equal to the}\\ \text{square root of all}\\ \text{of x2 minus x1 the whole square}\\ {\bf\text{ minus }}\\ \text{y2 minus y1 the whole square.} \)
so it is b right?
she didn't add the "x" components, so can't be "b"
ok i got it right as a
do u no this one Which statement about the centroid of a triangle is always true? It divides an altitude of a triangle into two parts where one part is 2 times the length of the other. It divides a triangle into two parts of equal area. It is located inside the triangle. It is located at the midpoint of a median.
what u need help on go to youtube and just type in math wrods
Look at triangle KLM. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0209_13/image0024e1b4754.jpg Which statement must be true? The three angle bisectors of the triangle will pass through point O. O is the orthocenter of the triangle and can lie either inside or outside a triangle. The perpendicular bisector of side KL will pass through point O. O is the center of the largest circle that can be drawn inside the triangle.
number 3
I guss?
A triangle can be classified by its angles and by its sides. Part 1: Use these two ways of classification to describe a right isosceles triangle. Part 2: Name a triangle with only a different angle classification as a right isosceles. Identify one similarity and one difference between this new triangle and the right isosceles triangle.
do u have link?
that way I can help u
ok i got tht one
what about Describe the process to construct an acute scalene triangle with vertices PQR using only a compass and straightedge, where Q is a point on a horizontal line segment XY.
I believe it's You can classify a triangle by its sides, or by its angles medals
this is my last one
Describe the process to construct an acute scalene triangle with vertices PQR using only a compass and straightedge, where Q is a point on a horizontal line segment XY.
draw a line XY and name the end Q and R open your compass to greater then the midpoint; arc it from both end and where the arcs cross draw a line; this line is then perp to XY
did this help
yes
give me medals
ok i am gonna add another question and i will give u medal there ok :D
ok
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