Question

how do i solve 5x-7y=9 4x+3y=33

Answer 1

this with it
multiple choice

Answer 2

I'm assuming that those are two separate equations that should look like this:
\(5x - 7y = 9\) and \(4x +3y = 33\)
In that case, choose one equation (it doesn't matter which one) and solve for a variable (again, it doesn't matter which one). Then, substitute the resulting expression into the other equation in place of the variable that you have chosen. I'll provide an example:
\(2x – 3y = –2\) and \(4x + y = 24\)
I'm going to choose the second equation and solve for y.
\(4x + y = 24 \)
First, isolate y by subtracting both sides by 4x:
\(y = 24-4x\)
If y had a coefficient(other than 1) you would divide both sides by that number. It doesn't so we are done with this step.
Now, Substitute \(24-4x\) for y in the other equation:
\(2x-3(24-4x) = -2\)
And solve this equation using Order of Operations. Parenthesis:
\(2x-72+12x = -2\)
Combine like terms by adding 72 to each side then combine the x terms:
\(14x = 70\)
Divide both sides by 14 to isolate the x:
\(x = 5\)
Now, substitute 5 into each equation and solve for y: (hint: you should get the same answer on each equation - this is how you know you are correct.)
\(2x – 3y = –2\) and \(4x + y = 24\)
\(2(5) – 3y = –2\) and \(4(5) + y = 24\)
\(10 – 3y = –2\) and \(20 + y = 24\)
\(-3y = -12\) and \(y = 4\)
\(y = 4\)

If there is anything that is unclear, please ask.

Answer 3

good job gypsy :)

Answer 4

Thanks Texaschic.

Answer 5

i dont see how you got 2x at the beginning of the problem @gypsy1274

Answer 6

@papsmurf I don't like providing answers, so I created a different example to explain the steps. The original poster was already offline when I answered this question.

Answer 7

ohh ok