Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6. y = -6x - 15 y = -6x - 20 y = -6x + 15 y = -6x + 20
all the lines have slope \(-6\) so you have to find the \(y\) intercept to see if it is -15, -20, 15, or 20
if you have \(y=-6x+b\) and since \((-2,-3)\) is on the graph you know that if \(x=-2\) then \(y=-3\) so you can put \[-3=-6\times (-2)+b\] and solve for \(b\)
let me know what you get
i got C ?
18
yeah i made a typo there, i dont mean to be a pain so lets just solve it
ok
\[-3=-6\times (-2)+b\] solve for \(b\) \[-3=12+b\] subtract 12 from both sides and get \[-15=b\]
so the line is \(y=-6x-15\)
ohhhhhhhh..... so A
yah first time i have seen A all week usually C
i dont quite get these yet.. i have 4 more.. would u mind?
sure what is the next one?
Choose the equation of the line passing through the point (6, -2) and parallel to y = x + 7. y = x + 8 y = x - 4 y = x + 4 y = x - 8
ok very similar to the last one all your choices have the same slope, namely \(1\) so you only need to find the \(y\) intercept in this case if \(x=6\) you have \(y=-2\) so you can solve \[-2=6+b\] in one easy step subtract \(6\) from both sides
what do you get this time?
if you are confused let me know
so it would be D then?
yes
cool! only 3 more!
next...
Choose the equation of the line passing through the point (-2, 6) and parallel to y = 1/2x - 8. y = 1/2x + 7 y = 1/2x + 5 y = 2x + 7 y = 2x + 5
ok parallel means has the same slope the slope of \(y=\frac{1}{2}x-8\) is evidently \(\frac{1}{2}\) so you can ignore the last two answers because they have slope 2
gotcha
again put \(x=-2,y=6\) and solve \[6=\frac{1}{2}\times (-2)+b\] for \(b\) can you do this or do you need help?
ill try but what do i do for the first step to get me started?
be careful with the signs
first step is to multiply \(\frac{1}{2}\times (-2)\)
so i got C as my final answer
we already ruled out C and D right?
opps meant A
\[6=\frac{1}{2}\times (-2)+b\] \[6=-1+b\] \[7=b\] right!
Choose the equation of the line passing through the point (-1, 3) and perpendicular to y = -1/3x + 7. y = 3x - 12 y = 3x + 6 y = 3x - 6 y = 3x
and cool!
kk so once again all the slopes are the same
so guess what? you have to solve \[3=3(-1)+b\] for \(b\) you getting the hang of this?
let me know what you get for \(b\) again be careful with the signs
so this one would be B!
you got it !
cool only one more!
Choose the equation of the line passing through the point (-3, -1) and perpendicular to y = 1/2x + 3. y = -2x - 7 y = -2x +5 y = 2x + 5 y = 2x - 7
k i will look, this time start and see if you can figure out what you have to solve
actually before we start, i hope it is clear that the slope of \(y=\frac{1}{2}+3\) is \(\frac{1}{2}\) do you know what the slope of the perpendicular line is?
oops i meant \(y=\frac{1}{2}x+3\) has slope \(\frac{1}{2}\)
ok
do you know what the slope of the perpendicular line would be? you have two choices in your answers, \(2\) or \(-2\)
2?
no actually it is \(-2\) the "negative reciprocal" i .e. flip it and change the sign
ohhh ok
so that rules out C and D
yes
i think that it is B
lets see point is (-3, -1), slope is \(-2\) so you must solve \[-1=-2\times (-3)+b\] giving \[-1=-6+b\] so \[b=5\] and the equation is \(y=-2x+5\) is that the one you picked?
lol no... thats ok though! thank you! can i ask you one more? haha
yea, but you did pick B right?
Choose the equation below that represents the line passing through the point (-5, 1) with a slope of 3/2 . y - 5 =3/2 (x + 1) y + 1 =3/2 (x - 5) y + 5 = -3/2(x - 1) y - 1 = 3/2(x + 5) and yes i picked B
y = -2x - 7 y = -2x +5 y = 2x + 5 y = 2x - 7 B is correct
wait do u mean -2 or 2?
so is the answer 2x - 7 or -2x-7
the correct answer was \(y=-2x+5\)
ok!
oooh nooooo
let me do it correctly
i made a mistake, sorry
its fine
\[-1=-2\times (-3)+b\] \[-1=6+b\] \[-7=b\] \[y=-2x-7\] is the correct answer
now to your last problem
ok :)
slope is \(m=\frac{3}{2}\) and the point is \((-5,1)\)
the "point-slope" formula is \[y-y_1=m(x-x_1)\]replace \(m\) by \(\frac{3}{2}\) , replace \(x_1\) by \(-5\) and replace \(y_1\) by \(1\)
y - 1 = 3/2 ( x + 5) ?
make a direct substitution with the numbers for the variables and get \[y-1=\frac{3}{2}(x-(-5))\] or \[y-1=\frac{3}{2}(x+5)\] yes, you got it!
not too bad was it?
nope! thank you so much!!!!!
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