System of Equations help?
\[\frac{ 4 }{ 5 }Fac-Fab \cos 30=0\] \[\frac{ 3 }{ 5 }Fac+Fab \sin 30 - 550=0\]
Solving for both Fac and Fab
My plan was to solve for Fac using the 2nd equation.
so by substitution, what's your question?
\[Fac= \frac{ -5 }{ 3 }Fab+916.669\] Then sub that equation into first equation. \[4/5[-5Fab/3+916.669]\]
er what happened to the sin(30)?
Simplifying, \[\frac{ -4 }{ 3 }Fab+1222.223-Fabcos30=0\]
double check your first step
\[\frac{ -4 }{ 3 }Fabsin30+1222.223-Fabcos30=0\]
better
this is the part where you grab a calculator and solve for F_ab
Im confused on this part. Would I move the Fab terms to the opther side to make positive and then try to reduce?
combine like terms
\[\frac{ 4 }{ 3 }Fabsin30+Fabcos30=1222.223\]
yes
Could I then pull out a Fab from both terms?
you could do that
you're not allowed to use calculators?
I could but I was not sure what to meant for using the solve?
The solve function under Math?
cos(30 ) = .866... sin (30) = .5 -4/3 *.5 Fab + .866 Fab = 1222.223
Wouldn't the 4/3 be positive?
gah you keep making mistakes left and right
one second Let Fab = x let Fac = y \[\frac{4}{5}y-x \cos(30) = 0\] \[\frac{3}{5}y-x \sin(30) -550= 0\] solving for y for 2nd equation \[y=\frac{5}{3}(550+xsin(30))\] substituting for y into first equation \[\frac{4}{5}\frac{5}{3}(550+xsin(30))-x cos(30)=0\] \[\frac{4}{3}(550+xsin(30))-xcos(30)=0\]
\[733.333+ \frac{4}{6} x - \frac{\sqrt{3}}{2} x=0\]
\[x(\frac{4}{6}-\frac{\sqrt{3}}{2})=-733.33333\]
\[x=\frac{-733.33333}{\frac{4}{6}-\frac{\sqrt{3}}{2}}\] then solve for y HOPEFULLY I DIDNT MAKE ANY MISTAKES WHEN SOLVING THIS NOTE, BE VERY CAREFUL WHEN DOING SYSTEMS OF EQUATIONS LIKE THIS AS A SINGLE MISTAKE CAN DRASTICALLY ALTER THE SOLUTION
Wow thanks for the step by step. Im assuming you got root 3/2 from the unit circle?
i have it memorized cos(30) = .866
when you use it often enough, you tend to memorize these things
Ok I see. Just checked online. cos30= root 3/2. Thanks for the help!
but that part is the reason why i suggested you grab calculator because the number is not a nice decimal
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