Question

really need HELP!!! The formula for that area of a triangle is A = 1/2}bh. If the base is 5\sqrt 3 and the height is \sqrt {18} , what is the area of this triangle in radical form?

Answer 1

\[Area = \frac{1}{2} \times \frac{5}{\sqrt{3}} \times \sqrt{18} = \frac{1}{2} \times 5 \times \sqrt{\frac{18}{3}}\]

simplify the fraction inside the radical for the answer.

Answer 2

@campbell_st
Perhaps the poster meant this:

\(A = \dfrac{bh}{2} \)

\(A = \dfrac{5 \sqrt{3} \times \sqrt{18} }{2} \)

Answer 3

well if thats the case its

\[Area = \frac{5 \times \sqrt{3 \times 18}}{2}\]

Answer 4

I dont have a calculator to find the sqaure root can someone do it please ?

Answer 5

\(Area = \large \frac{5* \sqrt{54}}{2} = \frac{5* \sqrt{9*6}}{2}=\frac{15\sqrt{6}}{2} \)
If you would not like the sqrt in your answer thennn
\( \sqrt{6}\) is approximately 2.45
sooo \( Area = \large \frac{15*2.45}{2}\)

Answer 6

so your answer would be 18.375 ?

Answer 7

yess aproximately

Answer 8

is this in radical form ??

Answer 9

nooooooo
Radical form is what I showed above

\( Area = \large \frac{15\sqrt{6}}{2}\)

Answer 10

what is the area of this triangle in radical form? in the question it says this so how would i write this ?

Answer 11

for the answer

Answer 12

There I showed u above

Answer 13

ok so can u tell me the final answer ?

Answer 14

i dont have that sqrt sign on my keyboard