Question

Write the equation of a line in slope-intercept form that passes through the points ( -2, 5) and (-2, 11).

Answer 1

you first need to find the slope.

slope =

(y2 - y1) / (x2 - x1)

Answer 2

Or you can use two point slope form:

\[\large \frac{x - x_1}{x-2 - x_1} = \frac{y - y_1}{y_2 - y_1}\]

Answer 3

uhhh..

Answer 4

im confused which way is easier and would i get the same answer?

Answer 5

Oh My latex work is wrong..

Answer 6

the more standard approach with these types of problems is to use (y2 - y1) / (x2 - x1)

y2 = 11
y1 = 5

can you fill in
x2
x1
?

Answer 7

\[\large \frac{x - x_1}{x_2 - x_1} = \frac{y - y_1}{y_2 - y_1}\]

Answer 8

Okay I did the work and I got 6/0=0 so did I do something wrong?

Answer 9

See here x coordinates are same..

So, this line is parallel to y axis..

Answer 10

x = -2 is the equation..

Answer 11

so the equation just deals with the x parts

Answer 12

or what not with the x=-2

Answer 13

See graphically

Answer 14

how would I get the improper fraction with that

Answer 15

an*

Answer 16

If the line is parallel to y axis then its equation will be : x = m

If the line is parallel to the x axis then its equation will be y = m

Answer 17

If I am not wrong then.. It will be..

Answer 18

You can get an improper fraction though, yes?

Answer 19

Irrespective the value of y, line will always pass through x = -2..

Answer 20

I am not getting you, Improper fraction?? I did not get you..

Answer 21

well part of the problem waws to get an improper fraction. It says that the Slope should be a reduced improper fraction.

Answer 22

was*

Answer 23

Here slope is 6/0 ie Infinity..

If you get infinity as your slope, line is parallel to y as in this case too..