@satellite73 Please help me with this one too! =) Given triangle ABC with a = 7, C = 37°, and B = 18°, find c. Round the answer to two decimal places. a. 13.63 b. 5.14 c. 18.56 d. 3.59 Given triangle ABC with b = 2, c = 4, and measure of angle A= 118 degrees, find a. Round the answer to two decimal places. a. 4.87 b. 3.53 c. 3.26 d. 5.25
let me get to a real computer
Okay! Thanks!
law of sines for the first one lets draw a reasonable triangle
Okay!
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what is angle A?
I think Angle A= 125 degrees.
yeah \(180-37-18=125\) good now use the law of sines to find c \[\frac{c}{\sin(37)}=\frac{7}{\sin(125)}\iff c=\frac{7\sin(37)}{\sin(125)}\] and a calculator
Alright! =)
let me know what you get
Okay! I'll start solving it!
Alright! I got 5.14.
Thank you for your help!
Could I get help with the second problem? I'm really bad at this stuff!
yeah but i have to draw a picture first
you should too
Okay I will
i will wait for yours and then show you my picture
Okay, it's posted now.
ok now i get to be a bit critical, so don't take it the wrong way look at your angle 118 does it look like at 118 degree angle?
i said that to one person one time and he got angry, but i don't mean it that way it is good to be able to draw a somewhat accurate picture it doesn't have to be exact, but it should be reasonable
Okay I'm sorry.
no no don't be sorry i just mean it will be easier if you draw a picture that represents the triangle one thing for sure, the 118 degree angle has to be larger than a 90 degree angle
Alright, I'll draw another one.
ok then i will show you the one i drew if i can still find it
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nicer
but we still have a problem the triangle is drawn correctly but the sides are not labelled correctly the side opposite angle A is a the side opposite angle B is b the side opposite angle C is c
Oh oops! Should I draw another?
you have c opposite angle A
lets try to modify the one you have
no that wont work let me draw one and explain
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now like your second one, 118 looks reasonable but here the sides are labelled opposite the corresponding angles also notice that the side of length 4 is approximately twice the side of length 2 that is why your second picture cannot work as well
if it is ok with you, i am going to delete your third picture, because although it is labelled correctly, the lengths of the sides are not right
That's fine go head!
ok take a look at the picture i drew and notice that 2 is in fact shorter than 4, which is a good thing right?
i mean it probably should be even shorter, but at least it is not the same size or larger this tells us that angle B will be the smallest angle, because it is opposite the smaller side now i forgot what side we were looking for, although we can get all angles and all sides
We're looking for side a.
ok fine first notice that if we were lucky we could use the law of sines, but we cannot in this case is it clear why?
Yes it is.
if we try it, we would say \[\frac{a}{\sin(118)}=\frac{2}{\sin(B)}\] but we need 3 of the 4 numbers to solve and we only have two of the four so we need law of cosines
in this case use \[a^2=b^2+c^2-2bc\cos(A)\] which in this specific example is \[a^2=2^2+4^2-2\times 4\times \cos(118)\]
i get \(a^2=23.76\) rounded, making \(a=\sqrt{23.76}=4.87\) again rounded
i hope that is one of your choices also i hope that it is clearer how to do these
Okay, thank you for your help.
yw
I now understand how to find the answer.
kk good luck
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