Question

HELP!!!!! What is the vertex in the quadratic function y = - 2x^2+ 12x - 4 ? Write your answer as an ordered pair.

Answer 1

x coordinate of the vertex is given by -b/(2a)
what is a and what is b?

Answer 2

A Is 2x^2 and b is 12 ???

Answer 3

a = -2
b = 12
we just take the number in fron of the x

Answer 4

so
\[\frac{-12}{2(-2)} = ?\]

Answer 5

ohh okay.. and is it 3

Answer 6

??

Answer 7

@xoxox123 Yes, the x-coordinate of the parabola is 3.

Now, substitute x = 3 into y = - 2x^2+ 12x - 4 to get the coordinate of the y value of the vertex.

Answer 8

(3,50)

I guess

Answer 9

is y -4?

Answer 10

oh sorry i was mistaken

the answer is

(3,14)

Answer 11

@killua_vongoladecimo

Code of conduct: OpenStudy values the Learning process - not the ‘Give you an answer’ process Don’t post only answers - guide the asker to a solution.

Answer 12

can someone help me find y ?

Answer 13

i'm sorry.....well then here is the solution

To get the x-coordinate of the vertex use the equation \[\frac{ -b }{ 2a }\] so it would be\[\frac{ -12 }{ -4 }\] or 3 so it is the x-coordinate.

To get the y-coordinate equate y to \[y=-2x^{2} + 12x - 4\] Then substitute 3 to x which results to -18 + 36 - 4 or 14

So the coordinates of the vertex are (3,14)

Answer 14

how would you do this one ?? What is the vertex in the quadratic function y = - 4x^2 + 8x - 3 ? Write your answer as an ordered pair.

Answer 15

@killua_vongoladecimo