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Mathematics 13 Online
OpenStudy (anonymous):

. Use Law of Cosines to find the missing side c:

OpenStudy (anonymous):

OpenStudy (mathstudent55):

\( b^2 = a^2 + c^2 - 2ac\cos B \)

terenzreignz (terenzreignz):

Where angle B is the angle that is opposite the missing side b.

OpenStudy (anonymous):

so 23sqr+9sqr=bsqr???

terenzreignz (terenzreignz):

Let's take it one step at a time... what are your values for a,c, and B?

OpenStudy (anonymous):

no idea..

OpenStudy (mathstudent55):

Look at the figure. The angles of the triangle are called A, B, and C. The opposite sides to those angles are called a, b, and c.

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

|dw:1374500839548:dw|

OpenStudy (mathstudent55):

Compare the drawing above with the figure you were given. B = 89 degrees a = 23 c = 9

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

In the formula for the law of cosines above, notice the variables are b, a, c, and B. You are given all of them except b, which you need to solve for.

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

\( b^2 = a^2 + c^2 = 2ac \cos B\) Now replace the variables with the known quantities: \(b^2 = 23^2 + 9^2 - 2(23)(9) \cos 89^o \)

OpenStudy (mathstudent55):

Using a calculator, you can evaluate the right side.

OpenStudy (anonymous):

sooo

OpenStudy (anonymous):

would it be 602

OpenStudy (anonymous):

602.77

OpenStudy (mathstudent55):

Good. \(b^2 = 602.77\) Now take the square root of 602.77 to find b.

OpenStudy (anonymous):

363330.11816650934210078557254899

OpenStudy (anonymous):

thts wat my calculator said

OpenStudy (mathstudent55):

Square root and squaring are two different things.

OpenStudy (anonymous):

ohhh ok

OpenStudy (anonymous):

24 or 17

OpenStudy (mathstudent55):

What kind of calculator do you have that shows you over 30 digits?

OpenStudy (anonymous):

computer calculator ^~^

OpenStudy (mathstudent55):

\(b= \sqrt{602.77} \) \(b = 24.55 \)

OpenStudy (anonymous):

alrighty thankyouuu

OpenStudy (mathstudent55):

Ok, that makes sense. I was thinking that that was too many digits to carry in a pocket calculator.

OpenStudy (mathstudent55):

wlcm

OpenStudy (mathstudent55):

BTW, what happenend to the statement of the problem? Weren't we looking for b? Now it says to look for c.

OpenStudy (anonymous):

o.o no idea

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