Question

1/2x + 1/3y = 0
1/4x - 1/2y = 8

What is the solution of the system

Answer 1

Have u tried it ??

Answer 2

yes i have but i keep getting confused @Anu2401

Answer 3

You can use substitution method . Just find the value of x from any one of the equation & put this value of x(Which will be in terms of y) into the other equation

Answer 4

that just sounded likw another lingo lol @Anu2401

Answer 5

Ok i"ll give u a hint . Have a look @ attachment ... Try to proceed from here

Answer 6

@cherie_magee: Can u proceed from here to solve the question ??

Answer 7

See it When u r done ........ Njoy

Answer 8

you can make this easier by multiplying the first equation by 6 and the second equation by 4 and this will get rid of the fractions

Answer 9

@Anu2401 is solving this system of equations:

\( \dfrac{1}{2x} + \dfrac{1}{3y} = 0 \)

\( \dfrac{1}{4x} - \dfrac{1}{2y} = 8 \)

Is that correct?

Is the system what Anu thinks it is or is it (which @texaschic101 is solving)?

\( \dfrac{1}{2}x + \dfrac{1}{3}y = 0 \)

\( \dfrac{1}{4}x - \dfrac{1}{2}y = 8 \)

Answer 10

@mathstudent55 : Thanks for pointing it out bro :)
Very nice analysis :)

Answer 11

so which set of equations is it ?

Answer 12

My guess is it's the second one, but it can be either.

Answer 13

well....I suppose when or if she responds, we will know......lol