HELP Find the solution to the system algebraically. Show all work for full credit. Leave your answers in fraction form. y=6x^2
7x+y=3

Question

HELP Find the solution to the system algebraically. Show all work for full credit. Leave your answers in fraction form. y=6x^2
                                       7x+y=3

whpalmer4 · Answer

Solve second equation for y in terms of x.  Replace y in first equation with that, giving you a quadratic, and solve by your favorite method.

anonymous · Answer

so how would you set this up as

whpalmer4 · Answer

7x+y=3
y=3-7x
6x^2=3-7x
6x^2+7x-3=0
Solve...

anonymous · Answer

so basically u plug y=6x^2 to y on the equation below which is 7x+6x^2=3 adn then you organize it so its 6x^2+7x=3 and then u move the 3 to other side which becomes -3 so

anonymous · Answer

basically u gotta facot 6x^2+7x-3 i would like to give you an answer but i wish you to try it out before i give you the answer

anonymous · Answer

is it 40 ?

whpalmer4 · Answer

Don't give them the answer, help them work it out.  Much more helpful in the long run.

anonymous · Answer

he didn t give me the answer ??

whpalmer4 · Answer

No, a quadratic has two unique solutions unless it is a perfect square. This is not, and 40 is incorrect.  Do you get a true number statement if you square 40, multiply by 6, add 7*40 to that and subtract 3?  If that equals 0, you have a solution.  Or a really big value of 0 :-)

anonymous · Answer

?

anonymous · Answer

I got 9877

whpalmer4 · Answer

He said he wanted to give you the answer.

Do you know the quadratic formula solution?  You have a = 6, b = 7, c =-3

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

whpalmer4 · Answer

That you got 9877 means 40 isn't the solution!

whpalmer4 · Answer

If 40 was the solution, you would get 0.  We are trying to find values of x such that $$6x^2+7x-3=0$$

anonymous · Answer

how would you find the values if x

anonymous · Answer

do you solve for x

whpalmer4 · Answer

Use the formula I gave you with the a,b,c

anonymous · Answer

.024316339???

anonymous · Answer

-7+7^2-(6)(-3)/(2)6

anonymous · Answer

thats what i did

anonymous · Answer

@xoxox123 : Have a look @ attachment bro U had tried your best

anonymous · Answer

thats not the same problem.. @Anu2401

anonymous · Answer

Thats same brother

whpalmer4 · Answer

@xoxox123  you forgot to do the square root and a multiplication when you did the formula, 

$$x=\frac{-7\pm\sqrt{7^2-4(6)(-3)}}{2(6)}=\frac{-7\pm\sqrt{121}}{12}=\frac{-7\pm11}{12}$$$$x=\frac{1}{3}, x=-\frac{3}{2}$$