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\[\frac{ 2 }{ 6x } + \frac{ 4 }{ 3x^2 }\]
Please help :(
first find the common denominator
\[\frac{ 1 }{ 3x } + \frac{ 4 }{ 3x^2 } ?\]
you have 2 4 2(x) + 4(2) ---- + ----- = ----------------- 6x 3x^2 6x^2
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oh, you can do it that way, then you have 1 4 1(x) + 4 ---- + ------ = ------------ 3x 3x^2 3x^2
So my final answer is \[\frac{ x + 4 }{ 3x^2 }?\]
correct
Awesome :) Thank you soooo much :)
yw :)
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