sin x cos x/sec x + csc x = sin x/csc x
Prove the identity

Question

anonymous · Answer

Is it this?$$\frac{\sin x\cdot\cos x}{\sec x}+\csc x = \frac{\sin x}{\csc x}$$

anonymous · Answer

I guess it got messed up in typing, it's the first two numbers over the second two number = sin x /cos x. 
In other words, csc x is next to sec x on the left side of the equation

anonymous · Answer

$$\frac{ \sin x \cos x }{\sec x + \csc x }= \frac{ sinx }{ cscx }$$

anonymous · Answer

$$\frac{ \sin x + \cos x }{ \sec x + \csc x }=\frac{ \sin x }{\csc x }$$

anonymous · Answer

it's not correct

anonymous · Answer

what you wrote is cot x = tan x

anonymous · Answer

Well, $$
\frac{\sin x}{\csc x}=\sin^2x
$$

anonymous · Answer

@Roya Oh does left side $=\cot x$ ?

anonymous · Answer

just multiply each part dom to the other part num

anonymous · Answer

yes it is and the right side is tan x , they couldn't be equal

anonymous · Answer

cscx(sinx+cosx)=sinx(secx+cscX) --> 1+cotx=tanx+1

anonymous · Answer

Thanks to Kevin's hint, I can get the left side to sin2x and the right side to sin^2 x.
They're still not the same?