Question

sin x cos x/sec x + csc x = sin x/csc x
Prove the identity

Answer 1

Is it this?\[\frac{\sin x\cdot\cos x}{\sec x}+\csc x = \frac{\sin x}{\csc x}\]

Answer 2

I guess it got messed up in typing, it's the first two numbers over the second two number = sin x /cos x.
In other words, csc x is next to sec x on the left side of the equation

Answer 3

\[\frac{ \sin x \cos x }{\sec x + \csc x }= \frac{ sinx }{ cscx }\]

Answer 4

\[\frac{ \sin x + \cos x }{ \sec x + \csc x }=\frac{ \sin x }{\csc x }\]

Answer 5

it's not correct

Answer 6

what you wrote is cot x = tan x

Answer 7

Well, \[
\frac{\sin x}{\csc x}=\sin^2x
\]

Answer 8

@Roya Oh does left side \(=\cot x\) ?

Answer 9

just multiply each part dom to the other part num

Answer 10

yes it is and the right side is tan x , they couldn't be equal

Answer 11

cscx(sinx+cosx)=sinx(secx+cscX) --> 1+cotx=tanx+1

Answer 12

Thanks to Kevin's hint, I can get the left side to sin2x and the right side to sin^2 x.
They're still not the same?