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Physics 9 Online
OpenStudy (anonymous):

For the reaction: 2N205 (g) -> 4N)2(g) the rate Law is: change in [02]/change in time = k[N205] At 300K, the half life is 2.50 * 1064 second and the activation energy is 103.3kJ/mol. At what temperature is the half life 400. second?

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