(3m^2-2m-35)/(m^2-6m+9) + (m+4)/(m-7)
Find the LCD

Question

(3m^2-2m-35)/(m^2-6m+9) + (m+4)/(m-7)
Find the LCD

austinl · Answer

$$\frac{(3m^2-2m-35)}{(m^2-6m+9)} + \frac{(m+4)}{(m-7)}$$
You would need to multiply the denominators together.

austinl · Answer

$$(m^2-6m+9)\times (m-7)$$

anonymous · Answer

So m^3-13m^2+51m-63???

anonymous · Answer

Do you multiply the denominators and then factor them??

austinl · Answer

I made an error....
$$\frac{m-7}{m-7}\times \frac{(3m2−2m−35)}{(m2−6m+9)}+\frac{(m+4)}{(m−7)}\times \frac{m^2-6m+9}{m^2-6m+9}$$
I believe this is what you need to do, apologies, I need caffeine.

anonymous · Answer

Why would I do that? I'm confused now. XD

austinl · Answer

Perhaps it'd be best if we got an expert in here. I am too tired to be doing this. I'm sorry.

austinl · Answer

@nincompoop care to take over?

anonymous · Answer

It is okay.

hero · Answer

Try factoring first before adding