Question

(3m^2-2m-35)/(m^2-6m+9) + (m+4)/(m-7)
Find the LCD

Answer 1

\[\frac{(3m^2-2m-35)}{(m^2-6m+9)} + \frac{(m+4)}{(m-7)}\]
You would need to multiply the denominators together.

Answer 2

\[(m^2-6m+9)\times (m-7)\]

Answer 3

So m^3-13m^2+51m-63???

Answer 4

Do you multiply the denominators and then factor them??

Answer 5

I made an error....
\[\frac{m-7}{m-7}\times \frac{(3m2−2m−35)}{(m2−6m+9)}+\frac{(m+4)}{(m−7)}\times \frac{m^2-6m+9}{m^2-6m+9}\]
I believe this is what you need to do, apologies, I need caffeine.

Answer 6

Why would I do that? I'm confused now. XD

Answer 7

Perhaps it'd be best if we got an expert in here. I am too tired to be doing this. I'm sorry.

Answer 8

@nincompoop care to take over?

Answer 9

It is okay.

Answer 10

Try factoring first before adding